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Sunny_sXe [5.5K]
2 years ago
5

The gaseous product of a reaction is collected in a 25.0-l container at 27

Chemistry
1 answer:
nataly862011 [7]2 years ago
4 0
To find the number of moles of gas we can use the ideal gas law equation, we dont need to use the mass of gas given as we only have to find the number of moles 
PV = nRT 
P - pressure - 300.0 kPa 
V - volume - 25.0 x 10⁻³ m³
n - number of moles 
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature in Kelvin - 27 °C + 273 = 300 K
substituting these values in the equation 
300.0 kPa x 25.0 x 10⁻³ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 300 K 
n = 3.01 mol 
number of mols of gas - 3.01 mol
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Calculate the magnitude of the current in amperes if the number of moles of hydrogen gas produced is 5.13×10−4 mol (from part A)
Marat540 [252]

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1.65 A

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The hydrogen gas dissociates following the equation:

H₂(g) → 2H⁺ + 2e⁻

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By the Faraday law, 1 mol of electrons produces 96500 C of charge, thus:

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1.026x10⁻³ mol ---- x

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2 years ago
The value of delta G at 141.0 degrees celsius for the formation of phosphorous trichloride from its constituent elements,
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Answer:

The correct answer is option E.

Explanation:

The Gibbs free energy is given by expression:

ΔG = ΔH - TΔS

ΔH = Enthalpy change of the reaction

T = Temperature of the reaction

ΔS = Entropy change

We have :

ΔH = -720.5 kJ/mol =  -720500 J/mol (1 kJ = 1000 J)

ΔS = -263.7 J/K

T = 141.0°C = 414.15 K

\Delta G = -720500 J/mol - (414.15 K\times (-263.7 J/K))

= -611,288.64 J/mol = -611.28 kJ/mol\approx -611.3 kJ/mol

The Gibb's free energy of the given reaction at 141.0°C is -611.3 kJ/mol.

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