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2 years ago

What is the iupac name of this structure?

Chemistry

1 answer:

alexgriva [62]2 years ago

5 0

Answer:

3–ethyl–4–methylhexane.

Explanation:

To name the above compound, do the following:

1. Determine the functional group of the compound.

2. Locate the longest continuous carbon chain. This gives the parent name of the compound.

3. Identify the substituent group attached to the compound.

4. Give the substituent the lowest possible count.

5. Combine the above to name the compound.

Now, we shall name the compound given in the question above as follow:

1. The compound contains only single bond. Therefore, the compound belong to the alkane family.

2. The longest continuous carbon chain is 6 i.e hexane.

3. The substituent group attached are:

i. Methyl, CH3.

ii. Ethyl, CH2CH3.

4. we shall name the substituents alphabetically i.e ethly will come before methyl. Therefore,

Ethyl is located at carbon 3.

Methy is located at carbon 4.

5. Therefore, the name of the compound is:

3–ethyl–4–methylhexane.

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If you gently shake a carbon dioxide fire extinguisher, you will feel the presence of liquid within the extinguisher What condit

scoundrel [369]

When we wish to convert a gas to liquid we have to either

a) decrease temperature

b) increase pressure

In case of fire extinguisher the CO2 is found to be in liquid state, this is as the CO2 is pressurized at high pressure which keeps CO2 in liquid state

the ideal pressure and temperature conditions when CO2 gas can be converted to CO2 gas

Pressure = 5 - 73 atm

Temperature = -57 to 31 degree Celsius

6 0

2 years ago

Paintball is a popular recreational activity that uses a metal tank of compressed carbon

Dovator [93]

Answer:

Explanation:

Here we have the mass of CO₂ added = 340 g

From

$Number \, of \, moles = \frac{Mass}{Molar \, mass}$

We have, where the molar mass of CO₂ is 44.01 g/mol

Therefore,

$Number \, of \, moles = \frac{340}{44.01} = 7.73 \, \, \, moles$

71. Included drawing attached

72. Here we have the pressure of the gas given by Charles law which can be resented as follows;

$\frac{P_1}{P_2} =\frac{T_1}{T_2}$

Where:

P₁ = Initial pressure = 6.1 atmospheres

P₂ = Final pressure

T₁ = Initial Temperature = 293 K

T₂ = Initial Temperature = 313 K

Therefore,

$P_2= T_2 \times \frac{P_1}{T_1} = 313 \times \frac{6.1}{293} = 3.312 \, \, \, atmospheres$

5 0

2 years ago

A 12.2-g sample of x reacts with a sample of y to form 78.9 g of xy. what is the mass of y that reacted?

Sonja [21]

We will assume that the only reactants are x and y and that the only product is xy.

Based on the law of mass conservation, mass is an isolated system that can neither be created nor destroyed.

Applying this concept to the chemical reaction, we will find that the total mass of the reactants must be equal to the total mass of the products,
therefore:
mass of x + mass of y = mass of xy
12.2 + mass of y = 78.9
mass of y = 78.9 - 12.2 = 66.7 grams

4 0

2 years ago

A sample of sodium reacts completely with 0.355 kg of chlorine, forming 585 g of sodium chloride. What mass of sodium reacted?

Kay [80]

Answer:

The mass of sodium that reacted is 230 grams

Explanation:

The balance equation of the reaction is first written .

sodium = Na

Chlorine = Cl2

sodium chloride = NaCl

2Na + Cl2 → 2NaCl

from the balance equation we calculate the molar mass involve in the reaction

Molar mass of sodium from the equation = 23(2) = 46 g

molar mass of sodium chloride from the eqaution = 23 × 2 + 35.5 × 2 = 46 + 71 = 117 g

If 46g of sodium is in 117 g of sodium chloride

? gram will be in 585 g of sodium chloride

cross multiply

46 × 585/117 = 26910/117 = 230 g

The mass of sodium that reacted is 230 grams

5 0

2 years ago

For the reaction of oxygen and nitrogen to form nitric oxide, consider the following thermodynamic data (Due to variations in th

CaHeK987 [17]

Answer:

a. 7278 K

b. 4.542 × 10⁻³¹

Explanation:

Let´s consider the following reaction.

N₂(g) + O₂(g) ⇄ 2 NO(g)

The reaction is spontaneous when:

ΔG° < 0 [1]

Let's consider a second relation:

ΔG° = ΔH° - T × ΔS° [2]

Combining [1] and [2],

ΔH° - T × ΔS° < 0

ΔH° < T × ΔS°

T > ΔH°/ΔS°

T > (180.5 × 10³ J/mol)/(24.80 J/mol.K)

T > 7278 K

First, we will calculate ΔG° at 25°C + 273.15 = 298 K

ΔG° = ΔH° - T × ΔS°

ΔG° = 180.5 kJ/mol - 298 K × 24.80 × 10⁻³ kJ/mol.K

ΔG° = 173.1 kJ/mol

We can calculate the equilibrium constant using the following expression.

ΔG° = - R × T × lnK

lnK = - ΔG° / R × T

lnK = - 173.1 × 10³ J/mol / (8.314 J/mol.K) × 298 K

K = 4.542 × 10⁻³¹

7 0

2 years ago