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lorasvet [3.4K]
1 year ago
15

What is the iupac name of this structure?

Chemistry
1 answer:
alexgriva [62]1 year ago
5 0

Answer:

3–ethyl–4–methylhexane.

Explanation:

To name the above compound, do the following:

1. Determine the functional group of the compound.

2. Locate the longest continuous carbon chain. This gives the parent name of the compound.

3. Identify the substituent group attached to the compound.

4. Give the substituent the lowest possible count.

5. Combine the above to name the compound.

Now, we shall name the compound given in the question above as follow:

1. The compound contains only single bond. Therefore, the compound belong to the alkane family.

2. The longest continuous carbon chain is 6 i.e hexane.

3. The substituent group attached are:

i. Methyl, CH3.

ii. Ethyl, CH2CH3.

4. we shall name the substituents alphabetically i.e ethly will come before methyl. Therefore,

Ethyl is located at carbon 3.

Methy is located at carbon 4.

5. Therefore, the name of the compound is:

3–ethyl–4–methylhexane.

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In the best Lewis structure for the fulminate ion, CNO–, what is the formal charge on the central nitrogen atom?
Andrews [41]

Answer : The formal charge on the central nitrogen atom is, (+1)

Explanation :

Resonance structure : Resonance structure is an alternating method or way of drawing a Lewis-dot structure for a compound.

Resonance structure is defined as any of two or more possible structures of the compound. These structures have the identical geometry but have different arrangements of the paired electrons. Thus, we can say that the resonating structure are just the way of representing the same molecule.

First we have to determine the Lewis-dot structure of CNO^-.

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, CNO^-

As we know that carbon has '4' valence electrons, nitrogen has '5' valence electrons and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in CNO^- = 4 + 5 + 6 + 1= 16

According to Lewis-dot structure, there are 8 number of bonding electrons and 8 number of non-bonding electrons.

Now we have to determine the formal charge for each atom.

Formula for formal charge :

\text{Formal charge}=\text{Valence electrons}-\text{Non-bonding electrons}-\frac{\text{Bonding electrons}}{2}

For structure 1 :

\text{Formal charge on O}=6-6-\frac{2}{2}=-1

\text{Formal charge on C}=4-2-\frac{6}{2}=-1

\text{Formal charge on N}=5-0-\frac{8}{2}=+1

For structure 2 :

\text{Formal charge on O}=6-4-\frac{4}{2}=0

\text{Formal charge on C}=4-4-\frac{4}{2}=-2

\text{Formal charge on N}=5-0-\frac{8}{2}=+1

For structure 3 :

\text{Formal charge on O}=6-2-\frac{6}{2}=+1

\text{Formal charge on C}=4-6-\frac{2}{2}=-3

\text{Formal charge on N}=5-0-\frac{8}{2}=+1

The best Lewis-dot structure is, structure 1.

Thus, the formal charge on the central nitrogen atom is, (+1)

3 0
2 years ago
You are experimenting on the effect of temperature on the rate of reaction between hydrochloric acid (HCl) and potassium iodide
erica [24]

Answer is "B - 700,000".<span>

<span>Kinetic energy of a single particle (atom or molecule)<span> is directly proportional to its temperature according to the following equation.</span></span>
           KE = (3kT)/2

<span>Where </span>KE<span> is the kinetic energy of a single atom/molecule (</span>J<span>), </span>k<span> is the Boltzmann constant (</span>1.381 × 10</span>⁻²³ J/K<span>) and </span>T<span> is the temperature (</span>K<span>) </span><span>

When temperature increases, then the kinetic energy increases.

<span>If kinetic energy of atoms increases, then there will be more motions which create many collisions.</span></span>

4 0
2 years ago
Read 2 more answers
Quinine, an antimalarial drug, is 8.63% nitrogen. There are two nitrogen atoms per molecule. What is the molecular weight of qui
Furkat [3]

Answer:

324.18 g/mol

Explanation:

Let the molecular mass of the antimalarial drug, Quinine is x g/mol

According to question,

Nitrogen present in the drug is 8.63% of x

So, mass of nitrogen = \frac {8.63}{100}\times x

Also, according to the question,

2 atoms are present in 1 molecule of the drug.

Mass of nitrogen = 14.01 amu = 14.01 g/mol (grams for 1 mole)

So, mass of nitrogen = 14.01×2 = 28.02

These 2 must be equal so,

\frac {8.63}{100}\times x=28.02

solving for x, we get:

<u>x = 324.18 g/mol</u>

6 0
2 years ago
93.2 mL of a 2.03 M potassium fluoride (KF) solution
Marrrta [24]

Answer:

1.98 M

Explanation:

Given data

  • Initial volume (V₁): 93.2 mL
  • Initial concentration (C₁): 2.03 M
  • Volume of water added: 3.92 L

Step 1: Convert V₁ to liters

We will use the relationship 1 L = 1000 mL.

93.2mL \times \frac{1L}{1000mL} = 0.0932 L

Step 2: Calculate the final volume (V₂)

The final volume is the sum of the initial volume and the volume of water.

V_2 = 0.0932L + 3.92 L = 4.01L

Step 3: Calculate the final concentration (C₂)

We will use the dilution rule.

C_1 \times V_1 = C_2 \times V_2\\C_2 = \frac{C_1 \times V_1}{V_2} = \frac{2.03 M \times 3.92L}{4.01L} = 1.98 M

3 0
2 years ago
Read 2 more answers
At a given set of conditions 241.8 kJ of heat is released when one mole of H2O forms from its elements. Under the same condition
yan [13]

Answer:

44Kj

Explanation:

These are the equations for the reaction described in the question,

Vaporization which can be defined as transition of substance from liquid phase to vapor

H2(g)+ 1/2 O2(g) ------>H2O(g). Δ H

-241.8kj -------eqn(1)

H2(g)+ 1/2 O2(g) ------>H2O(l).

Δ H =285.8kj ---------eqn(2)

But from the second equation we can see that it moves from gas to liquid, we we rewrite the equation for vaporization of water as

H2O(l) ------>>H2O(g)---------------eqn(3)

But the equation from eqn(2) the eqn does go with vaporization so we can re- write as

H2O ------> H2(g)+ 1/2 O2(g)

Δ H= 285.8kj ---------------eqn(4)

To find Delta h of the vaporization of water at these conditions, we sum up eqn(1) and eqn(4)

Δ H=285.8kj +(-241.8kj)= 44kj

5 0
2 years ago
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