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Ber [7]
1 year ago
9

Justin B. Believes that the temperature lowering during the fall months is what causes the color of the leaves to change. He set

up an experiment wherein he placed some plants in 80 degrees rooms and some in 60 degree rooms. He observed the color of the leaves for a total of 1 month. At the end of the month Justin observed that 3/4 of the plants in the 60 degree temperature had begun to change colors and only 1/4 of the plants in the 80 degree temperature began to change colors.
Chemistry
1 answer:
Taya2010 [7]1 year ago
5 0

Answer:

This question is incomplete, the remaining part of the question is:

What is the control group, independent variable and dependent variable?

Control group: Plants placed in 80 degree rooms

Independent variable: Change in temperature

Dependent variable: Change in color of leaves

Explanation:

The independent variable in a scientific experiment is the variable that the experimenter controls or manipulates in order to bring about a change in the dependent variable. In this experiment, the variable manipulated by Justin B is the TEMPERATURE CHANGE.

On the other hand, a variable is said to be dependent if it is the variable that responds to a change made to the independent variable or rather it is the outcome. In this experiment, Justin B is trying to see the outcome on the color change in leaves when exposed to a low temperature, hence, COLOR CHANGE IN LEAVES is the dependent variable.

Control group of an experiment is the group that receives no experimental treatment. It is the group the experimenter considers normal and hence is comparing with his experimental group. In this experiment, Justin B believes the leaves change color in a low temperature, hence, he placed some plants in a lower temperature (60 degree) in order to compare them with when the plants are placed in a higher temperature (80 degree). As far as this experiment is concerned, the plants placed in 80 degrees temperature are believed by Justin B not to undergo color change, hence, they are the CONTROL GROUP while the group he placed in 60 degrees temperature are what he is interested in, making them the EXPERIMENTAL GROUP

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Answer;

The total pressure is 1.107 atm.

Explanation;

The total pressure is the sum of the pressures of the three gases in the flask

Pressure (total) = 0.215 atm + 0.066 atm + 0.826 atm = 1.107 atm

= 1.107 atm.

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1 year ago
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Find the time Δt it takes the magnetic field to drop to zero. Express your answer in terms of some or all of the quantities a, B
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Δt= \frac{NB_0 \pi a^2 }{IR}

This because ε = dΦ/dt, and emf is a voltage so it can also be written as dΦ/dt = IR

Because ΔΦ= ABcosθ for each of the N loops and cosθ is just 1 here only A needs to be replaced, and it can be replaced with A=πr^2, which makes that part of the equation ΔΦ_m=N*B0*πa^2
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2 years ago
Naturally occurring iodine has an atomic mass of 126.9045 amu. A 12.3849-g sample of iodine is accidentally contaminated with 1.
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Answer:

127.0665 amu

Explanation:

Firstly, to answer the question correctly, we need to access the percentage compositions of the iodine and the contaminant iodine. We can do this by placing their individual masses over the total and multiplying by 100%.

We do this as follows. Since the mass of the contaminant iodine is 1.00070g, the mass of the 129I in that particular sample will be 12.3849 - 1.00070 = 11.3842g

The percentage abundances is as follows:

Synthetic radioisotope % = 1.0007/12.3849 * 100% = 8.1%

Since there are only two constituents, the percentage abundance of the 129I would be 100 - 8.1 = 91.9%

Now, we can use these percentages to get the apparent atomic mass. We get this by multiplying the percentage abundance’s by the atomic masses of both and adding together.

That is :

[8.1/100 * 128.9050] + [91.9/100 * 126.9045] = 10.441305 + 116.6252355 = 127.0665 amu

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1 year ago
Under standard conditions, a given reaction is endergonic (i.e., ΔG >0). Which of the following can render this reaction favo
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Answer:

Maintaining a high starting-material concentration can render this reaction favorable.

Explanation:

A reaction is <em>favorable</em> when <em>ΔG < 0</em> (<em>exergonic</em>). ΔG depends on the temperature and on the reaction of reactants and products as established in the following expression:

ΔG = ΔG° + R.T.lnQ

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T is the absolute temperature

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To make ΔG < 0 when ΔG° > 0 we need to make the term R.T.lnQ < 0. Since T is always positive we need lnQ to be negative, what happens when Q < 1. Q < 1 implies the concentration of reactants being greater than the concentration of products, that is, maintaining a high starting-material concentration will make Q < 1.

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1 year ago
What is the ratio of the concentration of potassium ions to the concentration of carbonate ions in a 0.015 m solution of potassi
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The ratio of the concentration of potassium ions (K⁺) to the concentration of carbonate ions (CO₃²⁻) = 2: 1

<h3>Further explanation</h3>

Stochiometry in Chemistry studies about chemical reactions mainly emphasizes quantitative, such as the calculation of volume, mass, amount, which is related to the number of actions, molecules, elements, etc.

Reaction equations are chemical formulations for reagents and product substances

Reaction coefficients are numbers in the chemical formula of substances involved in the reaction equation. Reaction coefficients are useful for balancing reagents and products.

The reaction coefficient shows the ratio of the number of moles or molecules of the reacting substance

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Molarity shows the number of moles of solute in every 1 liter of solution.

\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}

Electrolytes will dissociate into ions when dissolved in water

While non-electrolyte solutions do not produce ions

Electrolyte solutions can be

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Potassium carbonate (K₂CO₃) will dissociate into ions

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Comparison of reaction coefficients = mole ratio = concentration ratio for the same volume, so

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K⁺: CO₃²⁻ = 2.0.015: 1.0.015

K⁺: CO₃²⁻ = 0.03: 0.015 = 2: 1

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Keywords: reaction coefficients, potassium carbonate, electrolytes

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