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oksano4ka [1.4K]
2 years ago
14

Which property to put in which

Chemistry
1 answer:
NeTakaya2 years ago
6 0
In the Proton category: symbol p, and +1 charge
In the Neutron category: symbol n, 0 charge
In the Electron category: symbol e, -1 charge
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What is the melting point of a solution in which 3.5 grams of sodium chloride is added to 230 mL of water?
kirza4 [7]
We are going to use this equation:

ΔT = - i m Kf

when m is the molality of a solution 

i = 2

and ΔT is the change in melting point = T2- 0 °C

and Kf is cryoscopic constant = 1.86C/m

now we need to calculate the molality so we have to get the moles of NaCl first:

moles of NaCl = mass / molar mass

                         = 3.5 g / 58.44 

                         = 0.0599 moles


when the density of water = 1 g / mL and the volume =230 L

∴ the mass of water = 1 g * 230 mL = 230 g = 0.23Kg 

now we can get the molality = moles NaCl / Kg water

                                                =0.0599moles/0.23Kg

                                                = 0.26 m

∴T2-0 =  - 2 * 0.26 *1.86

∴T2 = -0.967 °C
8 0
2 years ago
Read 2 more answers
Electrons in __________ bonds remain localized between two atoms. electrons in __________ bonds can become delocalized between m
dsp73

Electrons in sigma <span>bonds remain localized between two atoms. Sigma </span><span>bond results from the formation of </span><span>a molecular orbital </span><span>by the end to </span><span>end overlap of atomic </span>orbitals. Electrons<span> in pi</span> bonds can become delocalized between more than two atoms. Pi bonds result from the formation of molecular orbital by side to side overlap of atomic orbitals. 

 

<span> </span>

7 0
2 years ago
Both black and white road surfaces radiate energy. at midnight on a starry night the warmer road surface is the
luda_lava [24]
The black road because during the day it absorbed more radiation than the with one
5 0
2 years ago
How much 2 M HBr is needed to neutralize 380 mL of 0.1 M NH4OH?
Nata [24]

Answer:

19ml

Explanation:

trust me

8 0
2 years ago
The specific heat capacity of a pure substance can be found by dividing the heat needed to change the temperature of a sample of
mrs_skeptik [129]

Answer:

The answers to your questions are given below.

Explanation:

Data obtained from the question include:

Mass (M) = 420.0 g

Temperature change (ΔT) = 43.8 °C

Specific heat capacity (C) = 3.52 J/g °C

Heat needed (Q) =...?

The heat needed for the temperature change can be obtained by using the following formula:

Q = MCΔT

Where:

Q is the heat needed measured in joule (J).

M is the mass of substance measured in grams (g)

C is the specific heat capacity of the substance with unit J/g °C.

ΔT is the temperature change measured in degree celsius (°C).

Thus, we can calculate the heat needed to change the temperature as follow:

Q = MCΔT

Q = 420 x 3.52 x 43.8

Q = 64753.92 J

Therefore, the heat needed to cause the temperature change is 64753.92 J

4 0
2 years ago
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