According to the equation of molarity:
Molarity= no.of moles / volume per liter of Solution
when we have the molarity=0.58 M and the beaker at 150mL so V (per liter) = 150mL/1000 = 0.150 L
by substitution:
∴ No.of moles = Molarity * Volume of solution (per liter)
= 0.58 * 0.150 = 0.087 Moles
Answer:
BHx, x=3
CHx, x=4
NHx, x=3
CH2Clx, x=2
Explanation:
We have to know that the value of x must depend on the valency of the central atom. If we look at each of the species;
Boron has a common valency of 3
Carbon has a common valency of 4
Nitrogen has a common valency of 3
The valency of each elements will determine the most likely value of x as outlined in the answer above.
We are asked to convert from units of kilometer per second to units of miles per year. To do this, we need a conversion factor which would relate the different units involved. We either multiply or divide this certain value to the original measurement depending on what is asked. From literature, we will find that 1 mile is equal to 1609 meters and 1000 m is equal to 1 kilometer. Also, we will find that 3600 s is equal to 1 hr, 24 hr is equal to 1 day and 365 days is equal to 1 year. We do the conversion as follows:
3.8 km / s ( 1000 m / 1 km ) ( 1 mile / 1609 meters ) ( 3600 s / 1 hr ) ( 24 hr / 1 day ) ( 365 days / 1 year ) = 74479055.3 miles per year
Answer:
This solution is quite lengthy
Total system = nRT
n was solved to be 0.02575
nH20 = 0.2x0.02575
= 0.00515
Nair = 0.0206
PH20 = 0.19999
Pair = 1-0.19999
= 0.80001
At 15⁰c
Pair = 0.4786atm
I used antoine's equation to get pressure
The pressure = 0.50
2. Moles of water vapor = 0.0007084
Moles of condensed water = 0.0044416
Grams of condensed water = 0.07994
Please refer to attachment. All solution is in there.
Answer:
Explanation:
mass ratio of oxygen and nitrogen in air at Miami
= 21 : 79
ratio of their moles
= 
( mol weight of oxygen is 32 and of nitrogen is 28 )
= .65625 : 2.8214
= 1 : 4.3
This ratio will also be maintained in the air of Denver though total pressure decreases there.
Partial pressure of oxygen in air at both the places
mole fraction of oxygen
= 
= .18868
partial pressure of oxygen at Denver
= .18868 x .83 x 760
= 119 mm.
