I just did guessed on the question and got it right. The answer is kinetic energy.
Answer:
B.
Solar energy is converted into chemical potential energy, which is found in the products like glucose.
Explanation:
Explanation:
<u>Physical properties of ZBr₂</u>
The compound is an ionic substance. Therefore it will have properties of ionic compounds. Some of these properties are:
- it is a hard solid usually with high melting points or a liquid with high boiling points.
- Soluble in water and insoluble in non-polar solvents.
- It can conduct electricity in aqueous solutions or in molten form.
- it will undergo a fast reaction.
<u>Z is a metal</u>
To form ionic compound, a metal will combine with a non-metal. Bromine is a non-metal and it is expected that Z will be a metal. This is because ionic bonds involves transfer of electron from one specie to the other. Metals are usually the donor and non-metals are the receptor. This is how ionic bond forms. The electrostatic attraction resulting from the ions produced the ionic bond.
<u>Formula of the oxide</u>
ZO
Z 0
+2 -2
It is obvious that Z has 2 valence electrons. It will lose the two valence electrons to attain stability.
Oxygen requires 2 electrons to resemble Neon. This combination will give a compound ZO.
Learn more:
ionic compounds brainly.com/question/6071838
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Part (a) :
H₂(g) + I₂(s) → 2 HI(g)
From given table:
G HI = + 1.3 kJ/mol
G H₂ = 0
G I₂ = 0
ΔG = G(products) - G(reactants) = 2 (1.3) = 2.6 kJ/mol
Part (b):
MnO₂(s) + 2 CO(g) → Mn(s) + 2 CO₂(g)
G MnO₂ = - 465.2
G CO = -137.16
G CO₂ = - 394.39
G Mn = 0
ΔG = G(products) - G(reactants) = (1(0) + 2*-394.39) - (-465.2 + 2*-137.16) = - 49.3 kJ/mol
Part (c):
NH₄Cl(s) → NH₃(g) + HCl(g)
ΔG = ΔH - T ΔS
ΔG = (H(products) - H(reactants)) - 298 * (S(products) - S(reactants))
= (-92.31 - 45.94) - (-314.4) - (298 k) * (192.3 + 186.8 - 94.6) J/K
= 176.15 kJ - 84.78 kJ = 91.38 kJ
Answer:
The equilibrium concentration of CH₃OH is 0.28 M
Explanation:
For the reaction: CO (g) + 2H₂(g) ↔ CH₃OH(g)
The equilibrium constant (Keq) is given for the following expresion:
Keq=
=14.5
Where (CH3OH), (CO) and (H2) are the molar concentrations of each product or reactant.
We have:
(CH3OH)= ?
(CO)= 0.15 M
(H2)= 0.36 M
So, we only have to replace the concentrations in the equilibrium constant expression to obtain the missing concentration we need:
14.5= 
14.5 x (0.15 M) x
= (CH₃OH)
0.2818 M = (CH₃OH)