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stiks02 [169]
2 years ago
12

Which of the following equilibrium expressions corresponds to a heterogeneous equilibrium?(a) Kc =[NH4+][OH−][NH3](b) Kc =[H+][C

2H3O2−][HC2H3O2](c) Kc =[Ag(NH3)2+][Cl−][NH3]2(d) Kc = [Ba2+][F−]2
Chemistry
1 answer:
Alex777 [14]2 years ago
6 0

Answer:

c. Kc = \frac{[Ag(NH_{3})_2^{+}][Cl^-]}{[NH_3]^2}}

d. Kc = [Ba^{2+}][F^{-}]^2

Explanation:

An heterogeneous equilibrium is defined as a system whose reactants, products, or both are in more than one phase.

Also, you must know in an equilibrium constant you don't take solids or pure liquids. Thus:

a. Kc = \frac{[NH_{4}^+][OH^-]}{[NH_3]}}

The reaction must be: NH₃(aq) + H₂O(l) ⇆ NH₄⁺(aq) + OH⁻(aq)  <em>All reactants are in the same phase.</em>

b. Kc = \frac{[H^+][C_2H_3O_{2}^-]}{[HC_2H_3O_2]}}

The reaction must be: HC₂H₃O₂(aq) ⇄ H⁺(aq) + C₂H₃O₂⁻(aq)  <em>All reactants are in the same phase.</em>

c. Kc = \frac{[Ag(NH_{3})_2^{+}][Cl^-]}{[NH_3]^2}}

The reaction must be:  2NH₃(aq) + AgCl(s) ⇄ Ag(NH₃)₂⁺(aq) + Cl⁻(aq)

<em>Reactants aren´t in the same phase. Heterogeneous equilibrium</em>

d. Kc = [Ba^{2+}][F^{-}]^2

The reaction must be: BaF₂(s) ⇆ Ba²⁺(aq) + 2F⁻(aq)

<em>Reactants aren´t in the same phase. Heterogeneous equilibrium</em>

I hope it helps!

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Answer:

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Explanation:

To solve this problem we need to use the <em>boiling-point elevation formula</em>:

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Where <em>Tsolution</em> and <em>Tpure solvent</em> are the boiling point of the CS₂ solution (47.52 °C) and of pure CS₂ (46.3 °C), respectively. Kb is the constant asked by the problem, and m is the molality of the solution.

So in order to use that equation and solve for Kb, first we <em>calculate the molality of the solution</em>.

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<em>Tsolution</em> - <em>Tpure solvent</em> = Kb * m

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