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2 years ago

At –45oC, 71 g of fluorine gas take up 6843 mL of space. What is the pressure of the gas, in kPa?

1 answer:

4 0

The moles of fluorine present are 71/19 = 3.74
Now, we know that one mole of gas at 273 K and 101.3 kPa (S.T.P.) occupies 22.4 liters
Volume of 3.74 moles at S.T.P = 3.74 x 22.4
Volume = 83.776 L = 83,776 mL

Now, we use Boyle's law, that for a given amount of gas,
PV = constant

P x 6843 = 101.3 x 83776
P = 1,240 kPa

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By mistake, a quart of oil was dumped into a swimming pool that measures 25.0 m by 30.0 m. The density of the oil was 0.750 g/cm

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The oil slick thick = 1.256 x 10⁻⁴ cm

<h3>Further explanation</h3>

Volume is a derivative quantity derived from the length of the principal

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2 years ago

Titration of a 20.0-mL sample of acid rain required 1.7 mL of 0.0811 M NaOH to reach the end point. If we assume that the acidit

Rasek [7]

Answer:

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Explanation:

Volume of NaOH = 1.7 ml = 0.0017 L

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$0.0811 M=\frac{n}{0.0017 L}$

n = 0.0001378 mol

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Then 0.0001378 mol of NaOH will neutralize:

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Concentration of sulfuric acid in the acid rain sample: x

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Concentration of sulfuric acid in the acid rain sample is 0.0034467 mol/L.

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2 years ago

For a particular reaction, the change in enthalpy is â9kJmole and the activation energy is 13kJmole. The enthalpy change (ÎH) an

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Answer:

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Please find the complete question in the attached file.

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2 years ago

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