Answer:
mass of U-235 = 15.9 g (3 sig. figures)
Explanation:
1 atom can produce -------------------------> 3.20 x 10^-11 J energy
x atoms can produce ----------------------> 1.30 x 10^12 J energy
x = 1.30 x 10^12 / 3.20 x 10^-11
x = 4.06 x 10^22 atoms
1 mol ----------------------> 6.023 x 10^23 atoms
y mol ----------------------> 4.06 x 10^22 atoms
y = 0.0675 moles
mass of U-235 = 0.0675 x 235 = 15.8625
mass of U-235 = 15.9 g (3 sig. figures)
Ideal solutions obey Raoult's law, which states that:
P_i = x_i*(P_pure)_i
where
P_i is the partial pressure of component i above a solution
x_i is the mole fraction of component i in the solution
(P_pure)_i is the vapor pressure of pure component i
In this case,
P_benzene = 0.59 * 745 torr = 439.6 torr
P_toluene = (1-0.59) * 290 torr = 118.9 torr
The total vapor pressure above the solution is the sum of the vapor pressures of the individual components:
P_total = (439.6 + 118.9) torr = 558.5 torr
Assuming the gas phase also behaves ideally, the partial pressure of each gas in the vapor phase is proportional to its molar concentration, so the mole fraction of toluene in the vapor phase is:
118.9 torr/558.5 torr = 0.213
21.28s
Explanation:
This is a rate problem.
Number of parts produced = 225
Time taken to produce= 8hours
Rate of production is the amount of parts produced in a duration of time.
Now convert 8 hours to minute;
60 minutes = 1hr
8 hours = 60 x 8 = 480minutes
Now:
Rate of production = 
= 0.47parts/minute
Now, to produce 10 parts;
It takes;
0.47 parts to be produced in 1 minute
10 parts would be produced in 
= 21.28s
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The answer to this question would be CrO3 or H2SO4. These reagents would efficiently accomplish the transformation of 2-methyl-3-cyclopentenol into 2-methyl-3-cyclopentenone. The synthetic strategy is used for the bond forming and transformation of the molecule. The reagent required depends on the type of molecule.
How many times has it halved?
24/2 = 12
12/2 = 6
6/2 = 3
It halved three times.
It halves once every 6 hours.
18 hours have passed.
