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kykrilka [37]
2 years ago
9

If a balloon contains 3.00 L of air that has a pressure of 36.74 psi, what is the gas volume (the volume of the balloon) once it

floats to the surface?
Chemistry
1 answer:
Troyanec [42]2 years ago
6 0

Answer:

7.5 L

Explanation:

At constant temperature and number of moles, Using Boyle's law  

{P_1}\times {V_1}={P_2}\times {V_2}

Given ,  

V₁ = 3.00 L  

V₂ = ?

P₁ = 36.74 psi = 2.5 atm (Conversion factor, 1 psi = 0.068046 atm)

P₂ = 1 atm  (Atmospheric pressure as it comes to surface)

Using above equation as:

{P_1}\times {V_1}={P_2}\times {V_2}

{2.5\ atm}\times {3.00\ L}={1\ atm}\times {V_2}

{V_2}=\frac{{2.5}\times {3.00}}{1}\ L

{V_2}=7.5\ L

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The wall would absorb extra heat during the day when the sun is out, then release the heat back into the room when the sun goes down.
8 0
2 years ago
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A) How many moles of CO2 and H2O are formed from 3.85 mole of propane C3H8 (This calculation needs to be done twice-once fro CO2
4vir4ik [10]

Answer:

a) 11.55 moles of carbon dioxide gas are formed from 3.85 mole of propane.

15.4 moles of water are formed from 3.85 mole of propane.

b)0.5176 moles of water are formed from 0.647 mole of oxygen gas.

0.1294 moles of propane are consumed.

Explanation:

C_3H_7+5O_2\rightarrow 3CO_2+4H_2O

a) Moles of propane = 3.85 moles

According to reaction, 1 mole of propane gives 3 moles of carbon dioxide gas.

Then 3.85 moles of propane will give:

\frac{3}{1}\times 3.85 mol=11.55 mol of carbon dioxide gas.

11.55 moles of carbon dioxide gas are formed from 3.85 mole of propane.

According to reaction, 1 mole of propane gives 4 moles of water gas.

Then 3.85 moles of propane will give:

\frac{4}{1}\times 3.85 mol=15.4 mol of water .

15.4 moles of water are formed from 3.85 mole of propane.

b) Moles of oxygen gas = 0.647 moles

According to reaction, 5 mole of oxygen gas gives 4 moles of water.

Then 0.647 moles of oxygen will give:

\frac{4}{5}\times 0.647 mol=0.5176 mol of water.

0.5176 moles of water are formed from 0.647 mole of oxygen gas.

According to reaction, 5 mole of oxygen gas reacts with 1 mole of propane.

Then 0.647 moles of oxygen will give:

\frac{1}{5}\times 0.647 mol=0.1294 mol of propane.

0.1294 moles of propane are consumed.

5 0
2 years ago
Determine the molar solubility of CuCl in a solution containing 0.050 KCl. Ksp of CuCl is 1.0 x 10-6
Volgvan

Answer:

2.0x10^{-5}\frac{mol}{L}

Explanation:

Hello!

In this case, since the dissolution of copper (I) chloride is:

CuCl(s)\rightarrow Cu^++Cl^-

And its equilibrium expression is:

Ksp=[Cu^+][Cl^-]

We can represent the molar solubility via the reaction extent as x, however, since there is 0.050 M KCl we immediately add such amount to the chloride ion concentration since KCl is readily ionized; therefore we write:

1.0x10^{-6}=(x)(0.050+x)

Thus, solving for x, we obtain:

1.0x10^{-6}=0.050x+x^2\\\\x^2+0.050x-1x10^{-6}=0

By using the quadratic equation, we obtain:

x_1=2.0x10^{-5}M\\\\x_2=-0.05M

Clearly, the solution is x_1=2.0x10^{-5}M because no negative results are

allowed. Therefore, the molar solubility is:

2.0x10^{-5}\frac{mol}{L}

Best regards!

5 0
2 years ago
The K w for water at 0 ∘ C is 0.12 × 10 − 14 M 2 . Calculate the pH of a neutral aqueous solution at 0 ∘ C . p H = Is a pH = 7.2
labwork [276]

Answer:

pH → 7.46

Explanation:

We begin with the autoionization of water. This equilibrium reaction is:

2H₂O  ⇄   H₃O⁺  +  OH⁻            Kw = 1×10⁻¹⁴         at 25°C

Kw = [H₃O⁺] . [OH⁻]

We do not consider [H₂O] in the expression for the constant.

[H₃O⁺] = [OH⁻] = √1×10⁻¹⁴   →  1×10⁻⁷ M

Kw depends on the temperature

0.12×10⁻¹⁴ = [H₃O⁺] . [OH⁻]  → [H₃O⁺] = [OH⁻]         at 0°C

√0.12×10⁻¹⁴ = [H₃O⁺] → 3.46×10⁻⁸ M

- log [H₃O⁺] = pH

pH = - log 3.46×10⁻⁸ → 7.46

5 0
2 years ago
20 PTS!!! What is the volume of a gas at 90.0°C, if it occupies 1.41 L at 170°C?
Margarita [4]

Answer:

1.72 L

Explanation:

Initial Temperature of the gas T =90°+273= 363 K

Initial Volume of the gas V1= 1.41 L

Final temperature of the gas T2= 170°c +273= 443 K

Final volume of the gas V2= ????

Using Charles law;

V1/T1 = V2/T2

V1T2= V2T1

V2= V1T2/T1

V2= 1.41×443/363

V2= 1.72 L

3 0
2 years ago
Read 2 more answers
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