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kykrilka [37]
2 years ago
9

If a balloon contains 3.00 L of air that has a pressure of 36.74 psi, what is the gas volume (the volume of the balloon) once it

floats to the surface?
Chemistry
1 answer:
Troyanec [42]2 years ago
6 0

Answer:

7.5 L

Explanation:

At constant temperature and number of moles, Using Boyle's law  

{P_1}\times {V_1}={P_2}\times {V_2}

Given ,  

V₁ = 3.00 L  

V₂ = ?

P₁ = 36.74 psi = 2.5 atm (Conversion factor, 1 psi = 0.068046 atm)

P₂ = 1 atm  (Atmospheric pressure as it comes to surface)

Using above equation as:

{P_1}\times {V_1}={P_2}\times {V_2}

{2.5\ atm}\times {3.00\ L}={1\ atm}\times {V_2}

{V_2}=\frac{{2.5}\times {3.00}}{1}\ L

{V_2}=7.5\ L

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