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UkoKoshka [18]
2 years ago
7

Suppose you are measuring the mass of a sample using a balance that employs a standard mass of density dw = 8.0 g/ml. what is th

e buoyancy correction (m/m\'), if the sample density is less than 8.0 g/ml?
Chemistry
1 answer:
sleet_krkn [62]2 years ago
5 0

The buoyant force formula is:

B = \rho Vg

where B is Buoyant force, \rho is density, V is displaced body volume and g is 9.806 ms^{-2} (standard gravity).

The standard mass density of the sample, \rho _{1} = 8 g/ml  

If the dansity of the sample, \rho _{2} < 8 g/ml

The buoyancy correction is determined by the ratio:

\frac{B_{1}}{B_{2}} = \frac{\rho_{1} Vg}{\rho_{2} Vg}

\frac{B_{1}}{B_{2}} = \frac{\rho_{1}}{\rho_{2}}

\frac{B_{1}}{B_{2}} = \frac{\rho_{1}}{\rho_{2}}>1

Hence, the the buoyancy correction is positive.

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Each response gives a pair of solutions. which pair of solutions should conduct electrical current equally well? 1. 0.10 m nh3 a
Crazy boy [7]

Answer : The correct answer is option 2 : 0.10 M NaCl and 0.10 M NaClO₄

Explanation :

Solutions are classified into 3 categories.

1) Strong electrolytes : These are the solutions that dissociate completely forming ions . They are good conductors of electricity.

Example : All strong acids, bases and the salts made by strong acid/base are strong electrolytes .

2) Weak electrolytes : These substances do not dissociate completely thereby forming fewer ions. They are weak conductors of electricity.

3) Non electrolytes : These are the substances that do not dissociate at all. They do not form ions in aqueous medium. They are bad conductors of electricity.

Let us take a look at the given options and find out what type of solution do we have .

Option 1 : NH₃ is a weak electrolyte whereas NH₄Cl is a strong electrolyte bcause NH₄Cl is made by combination of NH₃ and HCl ( HCl is a strong acid)

Therefore NH₃ would carry electricity less efficiently than NH₄Cl.

Option 2 : Both NaCl and NaClO₄ are strong electrolytes. Therefore they will conduct electrical current equally well

Option 3 : NaNO₃ is a strong electrolyte but HNO₂ is a weak electrolyte. Therefore they will not carry the current equally

Therefore the correct option is option 2

3 0
2 years ago
150.0 grams of AsF3 were reacted with 180.0 g of CCl4 to produce AsCl3 and CCl2F2. The theoretical yield of CCl2F2 produced, in
Kamila [148]
The chemical reaction would be written as 

2 AsF3<span> + 3 CCl4 = 2 AsCl3 + 3 CCl2F2
</span>
We use the given amounts of the reactants to first find the limiting reactant. Then use the amount of the limiting reactant to proceed to further calculations.

150 g AsF3 ( 1 mol / 131.92 g) = 1.14 mol AsF3
180 g CCl4 (1 mol / 153.82 g) = 1.17 mol CCl4

 Therefore, the limiting reactant would be CCl4 since it would be consumed completely. The theoretical yield would be:

1.17 mol CCl4 ( 3 mol CCl2F2 / 3 mol CCl4 ) = 1.17 mol CCl2F2

7 0
1 year ago
If Maria winks exactly 5 times every minute while she is awake and she sleeps exactly 8 hours a day, how many times does Maria w
irina1246 [14]
24 minus 8 is 16
5 times 60 is 300
300 times 16 is 4800.
She winks 4800 times a day
5 0
1 year ago
What element is being oxidized in the following redox reaction?
gregori [183]

Answer:

C is the element thats has been oxidized.

Explanation:

MnO₄⁻ (aq)  +  H₂C₂O₄ (aq)  →  Mn²⁺ (aq)  +  CO₂(g)

This is a reaction where the manganese from the permanganate, it's reduced to Mn²⁺.

In the oxalic acid, this are the oxidation states:

H: +1

C: +3

O: -2

In the product side, in CO₂ the oxidation states are:

C: +4

O: -2

Carbon from the oxalate has increased the oxidation state, so it has been oxidized.

4 0
2 years ago
A metal oxide with the formula mo contains 15.44% oxygen. in the box below, type the symbol for the element represented by m.
lana66690 [7]

<u>Answer:</u> The element represented by M is Strontium.

<u>Explanation:</u>

Let us consider the molar mass of metal be 'x'.

The molar mass of MO will be = Molar mass of oxygen + Molar mass of metal = (16 + x)g/mol

It is given in the question that 15.44% of oxygen is present in metal oxide. So, the equation becomes:

\frac{15.44}{100}\times (x+16)=16g/mol\\\\(x+16)=\frac{16g/mol\times 100}{15.44}\\\\x=(103.626-16)g/mol\\\\x=87.62g/mol

The metal atom having molar mass as 87.62/mol is Strontium.

Hence, the element represented by M is Strontium.

8 0
1 year ago
Read 2 more answers
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