One of the two products of this reaction is carbonic acid (H2CO3), which immediately forms water and the gas you identified after exposure to the flaming and glowing splints. Write a balanced equation showing the decomposition of carbonic acid.
To compute the energy, Q, needed to melt a certain amount of ice, n, in moles, we have

where the latent heat of fusion for ice is equal to 6.009 kJ/mol.
Now, since we have a 20.0 lb ice, we must first convert its mass to grams. Thus mass = (20.0)(1000)(0.4536) = 9072 g.
To find the number of moles present, we must recall that the molar mass of water (ice) is equal to <span>1.00794(2) + </span><span>15.9994 </span>≈ 18.01 g/mol. Hence, we have

Now, to compute for the molar heat of fusion, Q,

Therefore, the amount of heat needed to melt the 20-lb bag of ice is equal to 3026.9 kJ.
Answer: 3026.9 kJ
Answer:
Forward direction
Explanation:
The reaction quotient of an equilibrium reaction measures relative amounts of the products and the reactants present during the course of the reaction at particular point in the time.
Q < Kc , reaction will proceed in forward direction.
Q > Kc , reaction will proceed in backward direction.
Q = Kc , reaction at equilibrium.
It is the ratio of the concentration of the products and the reactants each raised to their stoichiometric coefficients. The concentration of the liquid and the gaseous species does not change and thus is not written in the expression.
Thus, for the reaction:
The expression is:
![Q=\frac {[CIO_3^{-}][Cl^{-}]^2}{[CIO^{-}]^3}](https://tex.z-dn.net/?f=Q%3D%5Cfrac%20%7B%5BCIO_3%5E%7B-%7D%5D%5BCl%5E%7B-%7D%5D%5E2%7D%7B%5BCIO%5E%7B-%7D%5D%5E3%7D)
Given,
[Cl⁻] = 0.50 mol/L; [ClO₃⁻] = 0.32 mol/L; [ClO⁻] = 0.24 mol/L
So,

Q = 5.7870
Since, Q < Kc (
)
The reaction will go in forward direction.
Percentage error is the relative error your measured value is from the true or accepted value. The formula for percentage error is written below:
Percentage error = |True Value - Measured Value|/True Value * 100
Percentage error = |0.75 g/mL - 0.78 g/mL|/0.75 g/mL * 100
Percentage error = 4%