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DaniilM [7]
2 years ago
8

Which element has 32 protons in its nucleus? phosphorus cobalt germanium sulfur

Chemistry
2 answers:
eduard2 years ago
8 0
<span>Germanium is the element that has 32 protons in its nucleus.</span>
Misha Larkins [42]2 years ago
4 0

The element that has 32 protons in its nucleus is GERMANIUM.

The elements in the periodic table are arranged in the order of increasing atomic number. The atomic number of an element is actually the number of protons in that element. For the question given above, the atomic number of germanium is 32, this implies that it has 32 protons in its nucleus. For a neutral atom, the number of proton and electron in the atom is the same. Thus, germanium also has 32 electrons.

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What will happen when a piece of magnesium metal is dropped into a beaker containing a l M solution of copper(1) chloride?
Julli [10]

Answer:

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Explanation:

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7 0
1 year ago
Devon’s laboratory is out of material to make phosphate buffer. He is considering using sulfate to make a buffer instead. The pk
sesenic [268]

Answer:

Is not possible to make a buffer near of 7.

Optimal pH for sulfate‑based buffers is 2.

Explanation:

The dissociations of H₂SO₄ are:

H₂SO₄ ⇄ H⁺ + HSO₄⁻ pka₁ = -10

HSO₄⁻ ⇄ H⁺ + SO₄²⁻ pka₂ = 2.

The buffering capacity is pka±1. That means that for H₂SO₄ the buffering capacity is in pH's between <em>-11 and -9 and between 1 and 3</em>, having in mind that pH's<0 are not useful. For that reason, <em>is not possible to make a buffer near of 7.</em>

The optimal pH for sulfate‑based buffers is when pka=pH, that means that optimal pH is <em>2.</em>

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I hope it helps!

4 0
2 years ago
What is a common factor associated with most severe storms?
Volgvan
A common factor is low pressure system. 
4 0
2 years ago
Read 2 more answers
Assuming equal concentrations and complete dissociation, rank these aqueous solutions by their freezing points. NH4l, CoBr3, Na2
seraphim [82]
Answer:

NaI > Na2SO4 > Co Br3

meaning that NaI has the highest freezing point, and Co Br3 has the lowest freezing point.

Explanation:

The freezing point depression is a colligative property.

That means that it depends on the number of solute particles dissolved.

The formula to calculate the freezing point depression of a solution of a non volatile solute is:

ΔTf = i * Kf * m

Where kf is a constant, m is the molality and i is the van't Hoff factor.

Molality, which is number of moles per kg of solvent, counts for the number of moles dissolved and the van't Hoff factor multipllies according for molecules that dissociate.

The higher the number of molecules that dissociate, the higher the van't Hoff, the greater the freezing point depression and the lower the freezing point.

As the question states that you assume equal concentrations (molality) and complete dissociation you just must find the number of ions generated by each solute, in this way:

NH4 I → NH4(+) + I(-) => 2 ions

Co Br3 → Co(+) + 3 Br(-) => 4 ions

Na2SO4 → 2Na(+) + SO4(2-) => 3 ions.

So, Co Br3 is the solute that generate more particles and that solution will exhibit the lowest freezing point among the options given, Na2SO4 is next and the NaI is the third. Ordering the freezing point from higher to lower the rank is NaI > Na2SO4 > CoBr3, which is the answer given.
4 0
1 year ago
The specific rotation of (R) carvone is (+) 61°. The optical rotation of a sample of a mixture of R &amp;S carvone is measured a
shusha [124]

Answer:

See explanation

Explanation:

% optical purity = specific rotation of mixture/specific rotation of pure enantiomer  * 100/1

specific rotation of mixture = 23°

specific rotation of pure enantiomer = 61°

Hence;

% optical purity = 23/61 * 100 = 38 %

More abundant enantiomer = 100% - 38 % = 62%

Hence the pure  (S) carvone is (-) 62° is the more abundant enantiomer.

Enantiomeric excess = 62 - 50/50 * 100 = 24%

Hence

(R) - carvone  =  38 %

(S) - carvone = 62%

7 0
1 year ago
Read 2 more answers
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