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Neko [114]
2 years ago
6

The molar heat capacity of an unknown substance is 92.1 J/mol-K. If the unknown has a molar mass of 118 g/mol, what is the speci

fic heat (J/g-K) of this substance?
Chemistry
1 answer:
dlinn [17]2 years ago
8 0

Answer : The specific heat (J/g-K) of this substance is, 0.780 J/g.K

Explanation :

Molar heat capacity : It is defined as the amount of heat absorbed by one mole of a substance to raise its temperature by one degree Celsius.

1 mole of substance releases heat = 92.1 J/K

As we are given, molar mass of unknown substance is, 118 g/mol that means, the mass of 1 mole of substance is, 118 g.

As, 118 g of substance releases heat = 92.1 J/K

So, 1 g of substance releases heat = \frac{92.1}{118}=0.780J/g.K

Thus, the specific heat (J/g-K) of this substance is, 0.780 J/g.K

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The Reaction: _S+O2=_SO2<br> How many moles of sulfur must be burned to give 0.567 moles of SO2?
Vesna [10]
Moles ratio:

1 S<span> + 1 </span><span>O2</span><span> = 1 </span><span>SO<span>2
</span></span>
1 mole S -------------- 1 mole SO2
? moles S ------------ 0.567 moles SO2

0,567 x 1 / 1

= 0.567 moles of S


3 0
2 years ago
Read 2 more answers
Which statement best describes the atoms of the gas neon? O They slide past each other. They move freely in all directions. O. T
timofeeve [1]

Answer:

The statement that describes the gas of neon is

1. They are far apart.

2. They move constantly.

3. They move freely in all directions.

4. They move at high speed. Neon is termed as a chemical element. It is a noble gas.

It is odorless, colorless, inert monatomic gas when under standard condition. Neon is the second of the rare gases to be discovered. The second lightest inert gas.

Explanation:i just know oki

7 0
2 years ago
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A solution surrounding a cell is hypertonic solution if: a. It contains fewer nonpenetrating solute particles than the interior
arlik [135]

Answer:

The answer is B. It contains more non-penetrating solute particles than the interior of the cell.

Explanation:

This means that it has a greater concentration or number of solute particles outside a membrane than there are inside it.

A typical example is Saline solution.

8 0
2 years ago
A NiCd battery uses nickel and cadmium to produce a potential difference. Using these equations, answer the following questions.
Dahasolnce [82]

Answer : The correct chemical reaction within the galvanic cell is,

(3) Cd(s)+2NiO(OH)(s)+2H_2O(l)\rightarrow 2Ni(OH)_2(s)+Cd(OH)_2(s)

Explanation :

Galvanic cell : It is defined as a device which is used for the conversion of the chemical energy produces in a redox reaction into the electrical energy. It is also known as the electrochemical cell.

The redox reaction occurs between the nickel and cadmium.

In the galvanic cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode.

The balanced two-half reactions will be,

Oxidation half reaction : Cd(s)+2OH^-(aq)\rightarrow Cd(OH)_2(aq)+2e^-

Reduction half reaction : NiO(OH)(aq)+H_2O(l)+e^-\rightarrow Ni(OH)_2(aq)+OH^-(aq)

Thus the overall reaction will be,

Cd(s)+2NiO(OH)(s)+2H_2O(l)\rightarrow 2Ni(OH)_2(s)+Cd(OH)_2(s)

6 0
2 years ago
4.82 g of an unknown metal is heated to 115.0∘C and then placed in 35 mL of water at 28.7∘C, which then heats up to 34.5∘C. What
nikitadnepr [17]

<u>Answer:</u> The specific heat of metal is 2.34 J/g°C

<u>Explanation:</u>

To calculate the mass of water, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of water = 1 g/mL

Volume of water = 35 mL

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{35mL}\\\\\text{Mass of water}=(1g/mL\times 35mL)=35g

When metal is dipped in water, the amount of heat released by metal will be equal to the amount of heat absorbed by water.

Heat_{\text{absorbed}}=Heat_{\text{released}}

The equation used to calculate heat released or absorbed follows:

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]      ......(1)

where,

q = heat absorbed or released

m_1 = mass of metal = 4.82 g

m_2 = mass of water = 35 g

T_{final} = final temperature = 34.5°C

T_1 = initial temperature of metal = 115°C

T_2 = initial temperature of water = 28.7°C

c_1 = specific heat of metal = ?

c_2 = specific heat of water = 4.186 J/g°C

Putting values in equation 1, we get:

4.82\times c_1\times (34.5-110)=-[35\times 4.186\times (34.5-28.7)]

c_1=2.34J/g^oC

Hence, the specific heat of metal is 2.34 J/g°C

4 0
2 years ago
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