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Rudiy27
2 years ago
6

Why are metallic crystals malleable and ductile? A. The electrons are free floating, allowing them to move with the atoms when t

he metal is struck and the crystal lattice shifts. B. The free floating electrons conduct energy easily, and disperse the energy of being hit by a hammer or other tool, allowing them to be molded and not break. C. The crystal lattice is made of very strong ionic bonds that take a lot of energy to break. D. The atoms are arranged with alternating positive and negative charges. When struck, the lattice shifts putting positives against positives and negatives against negatives.
Chemistry
1 answer:
jok3333 [9.3K]2 years ago
7 0

Answer:

D. The atoms are arranged with alternating positive and negative charges. When struck, the lattice shifts putting positives against positives and negatives against negatives.

Explanation:

Metallic crystals takes their properties as a result of metallic bonds in between the atoms.

Metallic bond is actually the attraction between the positive nuclei of all the closely packed atoms in the lattice and the electron cloud jointly formed by all the atoms by losing their outermost shell electrons this is by virtue of their low ionization energy.

Physical properties of metals such as malleability, ductility, electrical conductivity, etc can be accounted for by metallic bonds.

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A tank of 0.1m3 volume contains air at 25∘C and 101.33 kPa. The tank is connected to a compressed-air line which supplies air at
Dmitriy789 [7]

Answer:

Amount of Energy = 23,467.9278J

Explanation:

Given

Cv = 5/2R

Cp = 7/2R wjere R = Boltzmann constant = 8.314

The energy balance in the tank is given as

∆U = Q + W

According to the first law of thermodynamics

In the question, it can be observed that the volume of the reactor is unaltered

So, dV = W = 0.

The Internal energy to keep the tank's constant temperature is given as

∆U = Cv((45°C) - (25°C))

∆U = Cv((45 + 273) - (25 + 273))

∆U = Cv(20)

∆U = 5/2 * 8.314 * 20

∆U = 415.7 J/mol

Before calculating the heat loss of the tank, we must first calculate the amount of moles of gas that entered the tank where P1 = 101.33 kPa

The Initial mole is calculated as

(P * V)/(R * T)

Where P = P1 = 101.33kPa = 101330Pa

V = Volume of Tank = 0.1m³

R = 8.314J/molK

T = Initial Temperature = 25 + 273 = 298K

So, n = (101330 * 0.1)/(8.314*298)

n = 4.089891232222

n = 4.089

Then we Calculate the final moles at P2 = 1500kPa = 1500000Pa

V = Volume of Tank = 0.1m³

R = 8.314J/molK

T = Initial Temperature = 25 + 273 = 298K

n = (1500000 * 0.1)/(8.314*298)

n = 60.54314465936812

n = 60.543

So, tue moles that entered the tank is ∆n

∆n = 60.543 - 4.089

∆n = 56.454

Amount of Energy is then calculated as:(∆n)(U)

Q = 415.7 * 56.454

Q = 23,467.9278J

3 0
1 year ago
Explain what happens to an ionic substance when it dissolves in water. Drag the terms on the left to the appropriate blanks on t
nignag [31]

Answer:

false

Explanation:

5 0
2 years ago
Which of the following is a correctly written chemical equation that demonstrates the conservation of mass?
Fantom [35]

Answer:

Option D is correct.

H₂O + CO₂      →    H₂CO₃

Explanation:

First of all we will get to know what law of conservation of mass states.

According to this law, mass can neither be created nor destroyed in a chemical equation.

This law was given by French chemist  Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

Example:

6CO₂ + 6H₂O + energy → C₆H₁₂O₆ + 6O₂

there are six carbon atoms, eighteen oxygen atoms and twelve hydrogen atoms on the both side of equation so this reaction followed the law of conservation of mass.

Now we will apply this law to given chemical equations:

A) H₂ + O₂   →    H₂O

There are two hydrogen and two oxygen atoms present on left side while on right side only one oxygen and two hydrogen atoms are present so mass in not conserved. This equation not follow the law of conservation of mass.

B) Mg + HCl   →   H₂ + MgCl₂

In this equation one Mg, one H and one Cl atoms are present on left side while on right side two hydrogen, one Mg and two chlorine atoms are present. This equation also not follow the law of conservation of mass.

C) KClO₃      →     KCl + O₂

There are one K, one Cl and three O atoms are present on left side of chemical equation while on right side one K one Cl and two oxygen atoms are present. This equation also not following the law of conservation of mass.

D)  H₂O + CO₂      →    H₂CO₃

There are two hydrogen, one carbon and three oxygen atoms are present on both side of equation thus, mass remain conserved. Thus is correct option.

6 0
1 year ago
Green light has a frequency of about 6.00×1014s−1. What is the energy of a photon of green light?
Sindrei [870]

3.98 x 10⁻¹⁹ Joule

<h3>Further explanation</h3>

<u>Given:</u>

The green light has a frequency of about 6.00 x 10¹⁴ s⁻¹.

<u>Question:</u>

The energy of a photon of green light (in joules).

<u>The Process:</u>

The energy of a photon is given by \boxed{\boxed{ \ E = hf \ }}

  • E = energy in joules
  • h = Planck's constant 6.63 x 10⁻³⁴ Js
  • f = frequency of light in Hz (sometimes the symbol f is written as v)

Let us find out the energy of the green light emitted per photon.

\boxed{ \ E = (6.63 \times 10^{-34})(6.00 \times 10^{14}) \ }

Thus, we get a result of \boxed{\boxed{ \ E = 3.98 \times 10^{-19} \ J \ }}

- - - - - - - - - -

Notes

  • When an electron moves between energy levels it must emit or absorb energy.  
  • The energy emitted or absorbed corresponds to the difference between the two allowed energy states, i.e., as packets of light called photons.  
  • A higher energy photon corresponds to a higher frequency (shorter wavelength) of light.
<h3>Learn more</h3>
  1. The energy of the orange light emitted per photon brainly.com/question/2485282#
  2. Determine the density of our sun at the end of its lifetime brainly.com/question/5189537  
  3. Find out the kinetic energy of the emitted electrons when metal is exposed to UV rays brainly.com/question/5416146  

Keywords: green light, frequency, the energy, a photon, Planck's constant, electrons, emitted, wavelength, joules

7 0
2 years ago
The energy difference between the 5d and 6s sublevels in gold accounts for its color. Assuming this energy difference is about 2
sergejj [24]

Answer:

\lambda=459.1\times 10^{-7}\ m = 459.1 nm

This wavelength corresponds to yellow color and thus gold has warm yellow color.

Explanation:

Given that:- Energy = 2.7 eV

Energy in eV can be converted to energy in J as:

1 eV = 1.602 × 10⁻¹⁹ J

So, Energy = 2.7\times 1.602\times 10^{-19}\ J=4.33\times 10^{-19}\ J

Considering:-

E=\frac{h\times c}{\lambda}

Where,  

h is Plank's constant having value 6.626\times 10^{-34}\ Js

c is the speed of light having value 3\times 10^8\ m/s

\lambda is the wavelength of the light

So,  

4.33\times 10^{-19}=\frac{6.626\times 10^{-34}\times 3\times 10^8}{\lambda}

4.33\times \:10^{26}\times \lambda=1.99\times 10^{20}

\lambda=459.1\times 10^{-7}\ m = 459.1 nm

This wavelength corresponds to yellow color and thus gold has warm yellow color.

7 0
1 year ago
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