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Mariulka [41]
2 years ago
15

Gina made a poster for plastic recycling week and included this information on her poster: What corrections should Gina make? Ch

eck all that apply. Gina should put “cellulose” under “Synthetic.” Gina should put “plastic” under “Natural.” Gina should put “rubber tires” under “Synthetic.” Gina should put “starch” under “Natural.” Gina should put “DNA” under “Synthetic.” Gina should put “nylon” under “Natural.”
Chemistry
2 answers:
babymother [125]2 years ago
7 0

Answer:

C and D

Hope I could help <3

Basile [38]2 years ago
3 0
Gina should put “rubber tires” under “Synthetic.”<span>Gina should put “starch” under “Natural.”</span>
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Explanation:

idk why all u guys like trump who do.. hes just a big pain in the a*s.

8 1
1 year ago
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Consider the chemical reaction: N2 3H2 yields 2NH3. If the concentration of the reactant H2 was increased from 1.0 x 10-2 M to 2
Brilliant_brown [7]

The equilibrium constant of a reaction is defined as:

"The ratio between equilibrium concentrations of products powered to their reaction quotient and  equilibrium concentration of reactants powered to thier reaction quotient".

The reaction quotient, Q, has the same algebraic expressions but use the actual concentrations of reactants.

To solve this question we need this additional information:

<em>For this reaction, K = 6.0x10⁻² and the initial concentrations of the reactants are:</em>

<em>[N₂] = 4.0M; [NH₃] = 1.0x10⁻⁴M and [H₂] = 1.0x10⁻²M</em>

<em />

Thus, for the reaction:

N₂ + 3H₂ ⇄ 2NH₃

The equilibrium constant, K, of this reaction, is defined as:

K = 6.0x10^{-2} = \frac{[NH_3]^2}{[N_2][H_2]^3}

And Q, is:

Q = \frac{[NH_3]^2}{[N_2][H_2]^3}

Where actual concentrations are:

[NH₃] = 1.0x10⁻⁴M

[N₂] = 4.0M

[H₂] = 2.5x10⁻¹M

Replacing:

Q = \frac{[1.0x10^{-4}]^2}{[4.0][2.5x10^{-1}]^3}

<h3>Q = 1.6x10⁻⁷</h3>

As Q < K,

<h3>The chemical system will shift to the right in order to produce more NH₃</h3>

Learn more about chemical equililbrium in:

brainly.com/question/24301138

8 0
1 year ago
Compound X has the same molecular formula as butane but has a different boiling point and melting point. What can be concluded a
Vsevolod [243]
Compound X is an isomer of butane with different chain types. It is either straight chain or bend chain.
3 0
1 year ago
Problem Page A chemist measures the amount of bromine liquid produced during an experiment. He finds that of bromine liquid is p
masha68 [24]

The question is incomplete, here is the complete question:

A chemist measures the amount of bromine liquid produced during an experiment. She finds that 766.g of bromine liquid is produced. Calculate the number of moles of bromine liquid produced. Round your answer to 3 significant digits.

<u>Answer:</u> The amount of liquid bromine produced is 4.79 moles.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

We are given:

Given mass of liquid bromine = 766. g

Molar mass of liquid bromine, (Br_2) = 159.8 g/mol

Putting values in above equation, we get:

\text{Moles of liquid bromine}=\frac{766.g}{159.8g/mol}=4.79mol

Hence, the amount of liquid bromine produced is 4.79 moles.

6 0
1 year ago
What is the density of 96 ml of a liquid that has a mass of 90.5 g?
Otrada [13]

Answer:

Density = Mass / Volume.   so,  x = 90.5 g / 96 mL ... The Density would be 0.942 g/mL

8 0
2 years ago
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