Categorize the following materials: bronze alloy, mouse growing an ear on its back, porcelain dentures

An ice cube measuring 5.80 cm by 5.80 cm by 5.80 cm has a density of 0.917 g/mL What is the mass?

OLga [1]

Answer: 178.9 g

Explanation:

Density = $\frac{mass}{volume in mL}$

find volume of the cube: (5.80 cm) (5.80 cm) (5.80cm) = 195.112 cm³

1.0 cm³ = 1.0 mL

so 195.112 cm³ = 195.112 mL

plug value into density equation:

0.917 g/mL = (mass) / (195.112 mL)

and solve for mass!

3 0

1 year ago

A liquid with a high viscosity cannot be a mixture.

enot [183]

It can be made true by changing "cannot" to "can".

5 0

1 year ago

A compound that is composed of carbon, hydrogen, and oxygen contains 70.6% C, 5.9% H, and 23.5% O by mass. The molecular weight

zhannawk [14.2K]

Answer: The molecular formula will be $C_8H_8O_2$

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C= 70.6 g

Mass of H = 5.9 g

Mass of O = 23.5 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{70.6g}{12g/mole}=5.9moles$

Moles of H = $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{5.9g}{1g/mole}=5.9moles$

Moles of O = $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{23.5g}{16g/mole}=1.5moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{5.9}{1.5}=4$

For H = $\frac{5.9}{1.5}=4$

For O = $\frac{1.5}{1.5}=1$

The ratio of C : H: O= 4: 4:1

Hence the empirical formula is $C_4H_4O$

The empirical weight of $C_4H_4O$ = 4(12)+4(1)+1(16)= 68g.

The molecular weight = 136 g/mole

Now we have to calculate the molecular formula.

$n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{136}{68}=2$

The molecular formula will be= $2\times C_4H_4O=C_8H_8O_2$

4 0

2 years ago

Zircon is a mineral with the empirical formula ZrSiO4. If all the zirconium is 90Zr, all the silicon is 28Si, and all the oxygen

Romashka-Z-Leto [24]

Answer:

3.52g

Explanation:

Zr = 90 g/mol

Si = 28 g/mol

O = 16 g/mol

ZrSiO4 = 90 + 28 + (16* 4) = 182g/mol

Mass = Numberof moles * Molar mass

Mass = 1mol * 182g/mol = 182g

In one mole of ZrSiO4, there are 4 oxygen atoms, hence the mass is given as;

4 * 16 = 64g

Hence, 64g of oxygen is present in 182g of ZrSiO4.

10g would contain x

64 = 182

x = 10

x = ( 10 * 64 ) / 182

x = 640 / 182 = 3.52g

4 0

2 years ago

What is the total E associated with one mole of photons (a unit known as the Einstein) of 3.91x1019 Hz?

sashaice [31]

Answer:

$E=1.56\times 10^{10}J$

Explanation:

The<em> energy of a photon</em>, E, can be calculated with the Planck-Einstein equation:

$E=hf$

Where:

h is Planck's constant 6.626×10⁻³⁴ J.s, and

f is the frequency of the photon or electromagnetic radiation.

Substituting with your data:

$E=6.626\times 10^{-34}J.s\times 3.91\times 10^{19}s^{-1}=2.5908\times 10^{-14}J$

Now multiply by Avogadro's number to obtain the energy of one mole of photons:

$E=2.5908\times 10^{-14}J\times 6.022\times 10^{23}=1.56\times 10^{10}J$

8 0

1 year ago