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Fudgin [204]
2 years ago
9

What is the total E associated with one mole of photons (a unit known as the Einstein) of 3.91x1019 Hz?

Chemistry
1 answer:
sashaice [31]2 years ago
8 0

Answer:

        E=1.56\times 10^{10}J

Explanation:

The<em> energy of a photon</em>, E, can be calculated with the Planck-Einstein equation:

          E=hf

Where:

  • h is Planck's constant 6.626×10⁻³⁴ J.s, and
  • f is the frequency of the photon or electromagnetic radiation.

Substituting with your data:

          E=6.626\times 10^{-34}J.s\times 3.91\times 10^{19}s^{-1}=2.5908\times 10^{-14}J

Now multiply by Avogadro's number to obtain the energy of one mole of photons:

          E=2.5908\times 10^{-14}J\times 6.022\times 10^{23}=1.56\times 10^{10}J

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Answer:

k = 1.3 x 10⁻³ s⁻¹

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We are given the half life for the concentration of acetaldehyde to fall to one half its original value, thus

Ln [A]t/[A]₀ = Ln 1/2[A]₀/[A]₀= Ln 1/2 = - kt

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Reserpine is a natural product isolated from the roots of the shrub Rauwolfia serpentina. It was first synthesized in 1956 by No
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Answer:

  • Molality = 0.066 m
  • Molar mass = 608.36 g/mol

Explanation:

It seems the question is incomplete. However a web search us shows this data:

" Reserpine is a natural product isolated from the roots of the shrub Rauwolfia serpentina. It was first synthesized in 1956 by Nobel Prize winner R. B. Woodward. It is used as a tranquilizer and sedative. When 1.00 g reserpine is dissolved in 25.0 g camphor, the freezing-point depression is 2.63 °C (Kf for camphor is 40 °C·kg/mol). Calculate the molality of the solution and the molar mass of reserpine. "

The <em>freezing-point depression</em> is expressed by:

  • ΔT=Kf * m

We put the data given by the problem and <u>solve for m</u>:

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  • m = 0.06575 m

For the calculation of the molar mass:<em> Molality</em> is defined as moles of solute per kilogram of solvent:

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We<u> calculate moles of reserpine:</u>

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Finally we use the mass of reserpine and the moles to calculate <u>the molar mass</u>:

  • 1.00 g reserpine / 1.64x10⁻³ mol = 608.36 g/mol

<em>Keep in mind that if the data in your problem is different, the results will be different. But the solving method remains the same.</em>

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