How many mg does an 830 kg sample contain?

Valproic acid, used to treat seizures and bipolar disorder, is composed of C, H, and O. A 0.165-g sample is combusted to produce

sergeinik [125]

Answer:

The empirical formula is = $C_4H_8O$

The formula of Valproic acid = $C_8H_{16}O_2$

Explanation:

Mass of water obtained = 0.166 g

Molar mass of water = 18 g/mol

Moles of $H_2O$ = 0.166 g /18 g/mol = 0.00922 moles

2 moles of hydrogen atoms are present in 1 mole of water. So,

Moles of H = 2 x 0.00922 = 0.01844 moles

Molar mass of H atom = 1.008 g/mol

Mass of H in molecule = 0.01844 x 1.008 = 0.018588 g

Mass of carbon dioxide obtained = 0.403 g

Molar mass of carbon dioxide = 44.01 g/mol

Moles of $CO_2$ = 0.403 g /44.01 g/mol = 0.009157 moles

1 mole of carbon atoms are present in 1 mole of carbon dioxide. So,

Moles of C = 0.009157 moles

Molar mass of C atom = 12.0107 g/mol

Mass of C in molecule = 0.009157 x 12.0107 = 0.11 g

Given that the Valproic acid only contains hydrogen, oxygen and carbon. So,

Mass of O in the sample = Total mass - Mass of C - Mass of H

Mass of the sample = 0.165 g

Mass of O in sample = 0.165 - 0.11 - 0.018588 = 0.036412 g

Molar mass of O = 15.999 g/mol

Moles of O = 0.036412 / 15.999 = 0.002276 moles

Taking the simplest ratio for H, O and C as:

0.01844 : 0.002276 : 0.009157

= 8 : 1 : 4

The empirical formula is = $C_4H_8O$

Molecular formulas is the actual number of atoms of each element in the compound while empirical formulas is the simplest or reduced ratio of the elements in the compound.

Thus,

Molecular mass = n × Empirical mass

Where, n is any positive number from 1, 2, 3...

Mass from the Empirical formula = 4×12 + 8×1 + 16= 72 g/mol

Molar mass = 144 g/mol

So,

Molecular mass = n × Empirical mass

144 = n × 72

⇒ n = 2

The formula of Valproic acid = $C_8H_{16}O_2$

7 0

2 years ago

At a fixed volume, a four-fold increase in the temperature of a gas will lead to _______ in pressure.

aliina [53]

Answer:

Increase in pressure

Explanation:

The rise in temperature will increase the pressure of the gas.

6 0

2 years ago

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What happened to solid materials when mixed with the liquid materials?

KonstantinChe [14]

Answer:

the solid materials will disappear after mixing with a liquid material

plsss mark me as brainliest answer plsssssssss

5 0

2 years ago

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Consider this reaction: 2H+ + CO32- → H2O + CO2. Identify each of the following as a product, a reactant, or a coefficient.

givi [52]

Identify each of the following as a product or a coefficient in reaction below

<h2> 2H^+ + CO3^2- → H2O + CO2</h2><h2 /><h2 /><h3> reactant are</h3><h2> H^+ and CO3^2-</h2>

Reason: Reactant of a chemical reaction are found in the left side. They are initially present in a chemical reaction which are consumed to form product.

<h3> Product are</h3>

H2O and CO2

Reason: They are found in the right side of the reaction. Product are produced in a chemical reaction.

coefficient

 is 2

Coefficient is the number found in front of a formula.
Therefore 2 is the coefficient since it is found in front of H^+

5 0

2 years ago

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A galvanic cell employs the reaction Mg2+(aq) + Cu(s) → Mg(s) + Cu2+(aq) and NaNO3 is the salt used in the salt bridge. During t

sveta [45]

Answer:

b. Na+ leaves the salt bridge and enters enters the cathode

Explanation:

A galvanic cell or electrochemical cell depicts an oxidation -reduction half reactions (redox) reaction. it consists of two half cells ; one for the reduction reaction which involves the gain of electrons and the other for the oxidation reaction which involves the loss of electrons. One half cell contains the anode and oxidation occurs at the anode while the other half cell contains the cathode and reduction occurs at the cathode. The anode is usually connected to the cathode, a salt bridge is added to complete the circuit and allow current to flow. The salt bridge serves as a counter ions, they do not interfere with the electrochemical reaction but provides a passage for the migration of ions thereby preventing the cells from reaching equilibrium too quickly and thus the electrons in the salt are able to move along with any electrons.

In this galvanic cell, Cu at the anode losses two electrons to become Cu2+, and the electrons moves from the anode to the cathode where Mg2+ gain these two electrons to become negatively charged. Positively charged ions in the salt brigde Na+ will move to the cathode to pick negatively charged ions from the cathode solution. this helps to remove the strong negative charge from the cathode and allows the electrons to continue to move to the cathode.

8 0

2 years ago