For this type of problem, it is essential for you to have a data on the standard heats of formation of the substances given. For elemental substances or diatomic gases, the standard heat of formation is 0. Standard means the temperature is at 0°C and pressure at 1 atm. Calculate the standard heat of reaction using:
ΔH°rxn = ∑(Stoichiometric coefficient×ΔHf of products) - ∑(Stoichiometric coefficient×ΔHf of reactants)
Then, use this equation to find the reaction at T = 500°C and P = 1 bar:
ΔHrxn = ΔH°rxn + [∑(Stoichiometric coefficient×Cp of products) - ∑(Stoichiometric coefficient×ΔHf of reactants)]ΔT
So, you also need the Cp or specific heat capacities of the substances.
Answer:
1.3 L.
Explanation:
- Molarity is the no. of moles of solute per 1.0 L of the solution.
<em>M = (no. of moles of CaSO₄)/(Volume of the solution (L))</em>
<em></em>
M = 0.352 M.
no. of moles of CaSO₄ = mass/molar mass = (62.1 g / 136.14 g/mol) = 0.456 mol,
Volume of the solution = ??? L.
∴ (0.352 M) = (0.456 mol)/(Volume of the solution (L))
<em>∴ (Volume of the solution (L) </em>= (0.456 mol)/(0.352 M) = <em>1.296 L ≅ 1.3 L.</em>
Hello!
The statement that a solution of sodium acetate (CH₃COONa) is weakly basic is true:
Sodium acetate is the conjugate base of Acetic Acid. When sodium acetate is dissolved in water, it follows the equation that is shown below:
CH₃COONa(s) → CH₃COO⁻(aq) + Na⁺(aq)
Now the Acetate (CH₃COO⁻) ion, has an equilibrium in water to produce hydroxyl (OH⁻) ions and (Acetic Acid CH₃COOH)
CH₃COO⁻ + H₂O ⇄ CH₃COOH + OH⁻
This is a weak equilibrium, and the hydroxyl ions cause the solution to be weakly basic.
Have a nice day!