Answer:
The answer to your question is 50 moles of O₂
Explanation:
Balanced Chemical reactions
1.- N₂(g) + 3H₂ (g) ⇒ 2NH₃ (g)
2.- 4NH₃ (g) + 5O₂(g) ⇒ 4NO (g) + 6H₂O (l)
moles of N₂(g) = 20 moles
moles of O₂(g) = ?
Process
1.- Calculate the moles of NH₃
1 mol of N₂ ------------- 2 moles of NH₃
20 moles of N₂ --------- x
x = (20 x 2) / 1
x = 40 moles of NH₃
2.- Calculate the moles of O₂
4 moles of NH₃ -------------- 5 O₂
40 moles of NH₃ ------------ x
x = (40 x 5) / 4
x = 200 / 4
x = 50 moles of O₂
Answer:
The +3 oxidation state is characteristic of the actinides.
All actinides are radioactive.
Cerium (Ce) rnakes 100th in abundance (by mass %).
The actinides are silvery and chemically reactive.
The answer is strontium dihydrogen phosphate
That is strontium dihydrogen phosphate, is the compound containing the most hydrogen atoms per molecule or formula unit.
The formulas of the following compounds are as follows:
Hydrogen selenide H₂Se
Ammonium bromide NH₃Br
Strontium dihydrogen phosphate Sr(H₂PO4)₂
Sodium bicarbonate NaHCO₃
As it can be seen from the formula of strontium dihydrogen phosphate Sr(H₂PO4)₂
, that it contains the most hydrogen atoms per molecule or formula unit.
Answer:
bruh, just go in your bathroom and look for cleaning products
Explanation:
The correct answer is (3)
I-131 and P-32
The explanation:
according to attached table:
- we can see that the half life of p 32 is 14.28d (more than one hour)
- and the half life of I-131 is 8.021 d
(more than one hour)
and They both have β- decay mode and with half-lives greater than hour.
