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Oksanka [162]
2 years ago
12

A student in a chemistry laboratory has access to two acid solutions. The first one is 20% acid and the second solution is 45% a

cid.(The percentages are by volume). How many millilitres of each solution should the student mix together to obtain 100ml of a 30% acid solution?
Chemistry
1 answer:
Ksju [112]2 years ago
7 0

Volume of each solution : 60 ml 20% and 40 ml 45%

<h3>Further explanation</h3>

Given

20% and 45% acid

100 ml of 30% acid

Required

Volume of each solution

Solution

Molarity from 2 solutions :

Vm Mm = V₁. M₁ + V₂. M₂  

m = mixed solution

V = volume

M = molarity

V₁ = x ml

V₂ = (100 - x) ml

Input the value :

100 . 0.3 = x . 0.2 + (100-x) . 0.45

30 = 0.2x+45-0.45x

0.25x=15

x= 60 ml

V₁ = 60 ml

V₂ = 100 - 60 = 40 ml

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2 years ago
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What mass of boron sulfide must be processed with 2.1 x 10 4g of carbon to yield 3.11 x 10 4 g of boron and 1.47 x 10 5 g of car
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The reaction between boron sulfide and carbon is given as:

2B2S3 + 3C → 4B + 3CS2

As per the law of conservation of mass, for any chemical reaction the total mass of reactants must be equal to the total mass of the products.

Given data:

Mass of C = 2.1 * 10^ 4 g

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Now based on the law of conservation of mass:

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2 years ago
A student obtained a clean flask. She weighed the flask and stopper on an analytical balance and found the total mass to be 34.2
DanielleElmas [232]

Answer:

25.99mL is the volume internal volume of the flask

Explanation:

<em>To complete the question:</em>

<em>The temperature of the water was measured to be 21ºC. Use this data to find the internal volume of the stoppered flask</em>

<em />

The flask was filled with water, that means the internal volume of the flask is equal to the volume that the water occupies.

To find the volume of the water you need to find the mass and by the use of density of water at 21ºC (0.997992g/mL), you can find the volume of the flask, thus:

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Mass water = 25.935g of water.

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25.935g × (1mL / 0.997992g) =

<h3>25.99mL is the volume internal volume of the flask</h3>
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Answer:

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Answer:

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