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Oksanka [162]
2 years ago
12

A student in a chemistry laboratory has access to two acid solutions. The first one is 20% acid and the second solution is 45% a

cid.(The percentages are by volume). How many millilitres of each solution should the student mix together to obtain 100ml of a 30% acid solution?
Chemistry
1 answer:
Ksju [112]2 years ago
7 0

Volume of each solution : 60 ml 20% and 40 ml 45%

<h3>Further explanation</h3>

Given

20% and 45% acid

100 ml of 30% acid

Required

Volume of each solution

Solution

Molarity from 2 solutions :

Vm Mm = V₁. M₁ + V₂. M₂  

m = mixed solution

V = volume

M = molarity

V₁ = x ml

V₂ = (100 - x) ml

Input the value :

100 . 0.3 = x . 0.2 + (100-x) . 0.45

30 = 0.2x+45-0.45x

0.25x=15

x= 60 ml

V₁ = 60 ml

V₂ = 100 - 60 = 40 ml

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