Sodium Chloride because its still a liquid at the 773 temperature mark<span />
Hey there!:
From the given data ;
Reaction volume = 1 mL , enzyme content = 10 ug ( 5 ug in 2 mg/mL )
Enzyme mol Wt = 45,000 , therefore [E]t is 10 ug/mL , this need to be express as "M" So:
[E]t in molar = g/L * mol/g
[E]t = 0.01 g/L * 1 / 45,000
[E]t = 2.22*10⁻⁷
Vmax = 0.758 umole/min/ per mL
= 758 mmole/L/min
=758000 mole/L/min => 758000 M
Therefore :
Kcat = Vmax/ [E]t
Kcat = 758000 / 2.2*10⁻⁷ M
Kcat = 3.41441 *10¹² / min
Kcat = 3.41441*10¹² / 60 per sec
Kcat = 5.7*10¹⁰ s⁻¹
Hence kcat of xyzase is 5.7*10¹⁰ s⁻¹
Hope that helps!
Answer:
- Brush off any chemical dust around the balance after each use
- Alert your TA or instructor about any issues with the balance
Explanation:
The best practices while sharing a lab balance with other students includes alerting your TA or instructor about issues with the balance and Brushing off any chemical dust around the balance after each use. the practices will help to avert/reduce the work hazards associated with working with a balance.
Brushing off any chemical dust after each use will reduce the chemical hazards in the lab while Alerting your instructor about any issues with the balance helps to eliminate mechanical hazards that a faulty balance can pose
193.38 K was the initial temperature of the krypton.
Explanation:
Data given:
Initial volume of the krypton gas = 6 litres
initial pressure of the krypton gas = 0.960 atm
initial temperature of the krypton gas = ?
final volume of the krypton gas = 7.70 litres
final pressure of the Krypton gas = 1.25 atm
final temperature of the krypton gas = 55 degrees or 273.25+55 = 323.15 K
Applying the Combined Gas Laws:
Rearranging the equation:
T1 = 
Putting the value in the equation:
T1 = 
T1 = 193.38 K
Initial temperature of the krypton gas is 193.78 K
The balanced chemical reaction is:
CS2 + 3O2 = CO2 + 2SO2
First, we assume that the gases here are ideal and that the reaction is done at STP so that 22.4 L of the gas is equal to 1 mol. We use the reaction and the relation of the substances to calculate what is asked.
44.8 L (1 mol / 22.4 L) (1 mol CO2 / 2 mol SO2) (44.01 g / mol) = 44.01 g CO2
