Answer:-
0.91% is the students % of error
Explanation: -
Accepted value= 12.11 grams
Measured value = 12.22 grams
Error = 12.22-12.11 = 0.11 grams
Percentage error = 
x100
= 0.91 %
Thus 0.91% is the students % of error
Answer:
you need to send us the figure
Explanation:
Answer : The normality of the solution is, 30.006 N
Explanation :
Normality : It is defined as the number of gram equivalent of solute present in one liter of the solution.
Mathematical expression of normality is:
or,
First we have to calculate the equivalent weight of solute.
Molar mass of solute 
= 94.97 g/mole
Now we have to calculate the normality of solution.
Therefore, the normality of the solution is, 30.006 N
If 1 dozen apples has a mass of 2.0 kg and 0.20 bushel is 1 dozen apples, how many bushels of apples are in 1.0 kg of apples?
0.1 bushels
Answer:
Answer is explained below.
Explanation:
As (+) menthol and (-) menthol are enantiomers whose physical properties are same except optical activity so we can expect they have similar Rf values.
Whereas diastereomers have different physical properties and different Rf values.
For example when the (+) menthol , (-) menthol, isomenthol and neomenthol undergo TLC (thin layer chromatography) the
Rf values of.(+menthol) = .447
Rf (+isomenthol) = .395
Rf (+neomenthol)= .487
Rf (-menthol) = .434
The above data shows that (+) menthol and (-) menthol have almost same Rf values and vary a little i.e 0.447 and 0.437. So we can conclude them as enantiomers
Whereas (+) menthol or (+) neomenthol or (+) isomenthol i.e 0.447 , 0.395 and 0.487 have different Rf values. We can conclude them as diasteromers.
(+) menthol and (-) menthol - enantiomers
(+) menthol and (+) neomenthol- diastereomers
(-) menthol and (+) isomenthol - diastereomers
