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Rus_ich [418]
2 years ago
15

The volume of hcl gas required to react with excess ca to produce 11.4 l of hydrogen gas at 1.62 atm and 62.0 °c is ________ l.

Chemistry
1 answer:
seropon [69]2 years ago
3 0

Answer:

22.8 L  

Step-by-step explanation:

We can use <em>Gay-Lussac's Law of Combining Volumes</em> to solve this problem:

Gases <em>at the same temperature and pressure</em> react in simple whole-number ratios.

1. Write the chemical equation.

Ratio:                 2 L                             1 L

          Ca(s) + 2HCl(g) ⟶ CaCl₂(s) + H₂(g)

V/L:                                                     11.4

2. Calculate the volume of HCl.

According to the law, 2 L of HCl form 1 L of H₂.

Then, the conversion factor is (2 L HCl/1 L H₂).

Volume of HCl = 11.4 L H₂ × (2 L HCl/1 L H₂)

                         = 22.8 L HCl

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Answer:

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Explanation:

Given data:

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Solution:

First of all we will calculate the gram atom of each elements.

no of gram atom of carbon = 12 g / 12 g/mol = 1 g atoms

no of gram atom of hydrogen = 3 g / 1 g/mol = 3 g atoms

no of gram atom of oxygen = 8 g / 16 g/mol = 0.5 g atoms

Now we will calculate the atomic ratio by dividing the gram atoms with the 0.5 because it is the smallest number among these three.

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          C:H:O  =     2      :     6      :     1

The empirical formula of compound will be C₂H₆O

5 0
2 years ago
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Here we have to choose the right option which tells the moles of CaCl₂ will react with 6.2 moles of AgNO₃ in the reaction

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From the reaction: 2AgNO₃ + CaCl₂→ 2AgCl + Ca(NO₃)₂

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Henceforth, 6.2 moles of AgNO₃ reacts with \frac{6.2}{2} = 3.1 moles of CaCl₂.

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2 years ago
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<h3>Explanation:</h3>

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