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Ganezh [65]
2 years ago
14

A student determines measures the mass of one mole of carbon and finds it to be 12.22 grams. if the accepted value is 12.11 gram

s, what is the students % of error.
Chemistry
1 answer:
Gre4nikov [31]2 years ago
5 0

Answer:-

0.91% is the students % of error

Explanation: -

Accepted value= 12.11 grams

Measured value = 12.22 grams

Error = 12.22-12.11 = 0.11 grams

Percentage error = \frac{0.11 grams}{12.11 grams}x100

                           = 0.91 %

Thus 0.91% is the students % of error

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A new student is planning to use thin layer chromatography (TLC) for his research project. After setting up the apparatus the st
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Answer:

The open system evaporates the solvent in the solution

Explanation:

An open system is a system in which exchange of materials and energy can occur. If a TLC set up is left open, then the set up constitutes an open system.

During TLC, the sample is dotted on the plate and inserted into a suitable solvent. The solvent moves up the plate and achieves the required separation of the mixture.

Most of these solvents used used TLC are volatile organic compounds. Therefore, if the TLC set up is left open, the solvent will evaporate leading to poor results after running the TLC experiment.

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A student is given two 10g samples, each a mixture of only NaCl(s) and KCl(s) but in different proportions. Which of the followi
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Answer:

The information that can be used to determine which mixture has the higher proportion of KCl IS INFORMATION ABOUT THE MASS OF CHLORINE IN EACH MIXTURE, THIS INFORMATION CAN BE OBTAINED BY USING THE LAW OF DEFINITE PROPORTION.

Explanation:

The law of definite proportion states that the chemical composition by mass of a chemical compound is always constant. For instance, a chemical compound that is made up of two elements will always contain the same proportions of the constituent elements regardless of the quantity of chemical that was used.

Using the law of definite proportion, we can determine the proportion of sodium and chlorine in NaCl and the proportion of potassium and chlorine in KCl if the mass of chlorine that was used is known. Based on the results obtained, one can easily determine the mixtures that has higher proportion of KCl.

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2 years ago
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The ions Ca2+ and PO43- form salt with the formula
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Ca3(PO4)2 is the answer.

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1. The specific heat capacity of iron is 0.461 J g–1 K–1 and that of titanium is 0.544 J g–1 K–1. A sample consisting of a mixtu
mezya [45]

Answer:

The answer is 80,1 °C

Explanation:

Let´s start from the mass of the sample and the heat capacities:

First of all, we must calculate an average heat capacity. That's because we have a mixture and it is unknown the heat capacity of the whole sample.

The way we should do this calculation is as follows:

(1) H_{average}=Mass Fraction_{first component}* H_{first component}+MassFraction_{secondcomponent}*H_{second component}

For example, the mass fraction of Fe is simply:

(2) MassFraction_{Fe}=\frac{10g Fe}{10g Fe + 10gTi}=0.5

If you combine the equations (1) and (2) you have:

(3) H_{average}=0.5*0.461+0.5*0.544=0.5025\frac{J}{g-K}

Once calculated the average heat capacity we can solve the problem taking into account the corresponding equation:

(4) Q=m*H_{average}*(T_2-T_1)

Remember that:

<em>Q:</em> Heat gained or lost

<em>m</em>: Mass of the sample you want to analize

H_{average} : The value obtained in equation (3)

T_2: Final temperature of the sample

T_1: Initial temperature of the sample

Now we must replace the problem data in equation (4)

Take into account:

  • Heat gained in a system have a positive value
  • Heat lost in a system have a negative value
  • In this problem the sample loses 200 J, for this reason Q=-200J
  • The mass of the whole sample is: 10g of Fe + 10g of Ti = 20g of sample
  • The temperatures must be in absolute units of temperature (these are: rankine or kelvin)
  • The initial temperature of the system is 100°C or 373K

Now we are ready to use equation (4):

(5) -200J=20g*0.5025\frac{J}{g*K} *(T_2-373K)

It is clear that the unknown in equation (5) is T_2

The next step is to calculate T_2. Don't forget the signs; these are important.

Key concept: <u>Since the system is loosing heat, the final temperature of the system ( T_2) should be lower than the initial temperature ( T_1 )</u>

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Answer:

Find the list and explanation below.

Explanation:

Hydrochloric acid shortened as HCl is a harmful chemical when not handled properly. Four ways to avoid injury with hydrochloric acid include;

1. Dilution: It is advised to dilute the concentrated hydrochloric acid with a reasonable amount of water so that its corrosive effect can be significantly reduced.

2. Wear a laboratory coat: When working with hydrochloric acid in the laboratory it is always advised to wear a laboratory suit so as to ensure a minimal amount of harm in case of an accident or spillage with the acid.

3. Wear a face shield: It is also important that a face shield is worn while working with the acid to prevent contact with the eyes.

4. Wear a protective rubber glove: The rubber gloves would ensure that there is minimal contact of the acid with the hands.

Three steps to be taken in case of an accidental exposure include;

1. Medical Attention: In serious cases, such as in a case of ingesting the acid, urgent medical help should be sought for immediately.

2. Water: If there is contact with the skin or eye, a lot of water should be used on the affected area, and then medical help obtained.

3. Inhalation of fresh air: In a case whereby the hydrochloric acid was inhaled for a long time, the affected person should try to get some fresh air and if other effects are noticed, urgent medical attention should be gotten.

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