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igor_vitrenko [27]
2 years ago
5

Use the words protons neutrons and I suppose in the same sentence ​

Chemistry
1 answer:
PolarNik [594]2 years ago
5 0

Answer:

Isotopes have the same number of protons but a different number of neutrons.

Explanation:

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Bobby's mom sets a small pot of water on the stove and lights the burner. Ten minutes later, Bobby notices small bubbles and see
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A student measures a volume as 25 mL, whereas the correct volume is 23 mL. What is the percent error? * O 8.7% O 0.92% O 0.087%
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no u

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Draw the Lewis structure for CH3CH2O2H?
kotegsom [21]

Answer:

hydroperoxyethane

Explanation:

tomsFor the Lewis structure we have to remember that all the atoms must have <u>8 electrons</u> (except for hydrogen). In this structure, we have three types of atoms, Carbon, Hydrogen and Oxygen. So, we have to remember the <u>valence electrons</u> for each atom:

-) Carbon : 4 electrons

-) Hydrogen: 1 electron

-) Oxygen: 6 electrons

We can start with the "CH_3" part. We can put 3 hydrogen bond arroun the carbon. We can use this same logic with  "CH_2". Finally for oxygens, we can put it one bond with CH_2 and a bond between oxygens with a final bond with hydrogen to obtain <u>hydroperoxyethane</u>.

See figure 1 for further explanations.

6 0
2 years ago
Suppose 300 mL of 0.50 M lithium bromide solution and 300 mL of 0.70 M rubidium bromide solution are combined. What is the conce
GalinKa [24]

Answer:

0.60 mol·L⁻¹  

Explanation:

Data:  

LiBr: c = 0.50 mol/L; V =300 mL

RbBr: c = 0.70 mol/L; V =300 mL

1. Calculate the moles of Br⁻ in each solution

(a) LiBr

\text{Moles} = \text{0.300 L} \times \dfrac{\text{0.50 mol}}{\text{1 L}} = \text{ 0.150 mol}

(b) RbBr

\text{Moles} = \text{0.300 L} \times \dfrac{\text{0.70 mol}}{\text{1 L}} = \text{ 0.210 mol}

2. Calculate the molar concentration of Br⁻

(a) Moles of Br⁻

n = 0.150 mol  + 0.210 mol = 0.360 mol

(b) Volume of solution

V = 300 mL + 300 mL = 600 mL = 0.600 L

(c) Molar concentration

c = \dfrac{\text{moles}}{\text{litres}} = \dfrac{\text{0.360 mol}}{\text{0.600 L}} =  \textbf{0.60 mol/L}

 

6 0
1 year ago
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2.00 liters of hydrogen, originally at 25.0 °C and 750.0 mm of mercury, are heated until a volume of 20.0 liters and a pressure
dedylja [7]

Answer:  The new temperature is 10643 K

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 750.0 mm Hg = 0.98 atm   (760mmHg=1atm)

P_2 = final pressure of gas = 3.50 atm

V_1 = initial volume of gas = 2.00 L

V_2 = final volume of gas = 20.0 L

T_1 = initial temperature of gas = 25.0^oC=273+25.0=298.0K

T_2 = final temperature of gas = ?

Now put all the given values in the above equation, we get:

\frac{0.98\times 2.00}{298.0K}=\frac{3.50\times 20.0}{T_2}

T_2=10643K

Thus the new temperature is 10643 K

6 0
1 year ago
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