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2 years ago

Which statement is true about molarity and percent by mass?

Chemistry

2 answers:

Serga [27]2 years ago

8 0

<h3>The answer is D, They are different units of concentration. </h3>

Triss [41]2 years ago

5 0

Answer : The correct option is, They are different units of concentration.

Explanation :

Molarity : It is defined as the number of moles of solute present in one liter of solution.

Formula of molarity :

$\text{Molarity}=\frac{\text{Moles of solute}}{\text{Volume of solution in liters}}$

Mass percent : It is defined as the mass of solute present in the mass of solution.

Formula of mass percent :

$\text{Mass percent}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100$

Hence, both are the different unit of concentration.

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Chemists use letters of the alphabet as ____ for the elements.

d1i1m1o1n [39]

Answer:

The symbol is the right answer.

Explanation:

The “ Symbol” is the correct answer because chemist uses the letters of the alphabet to denote the element. For instance, the element oxygen is denoted by the letter of the alphabet “O”, the hydrogen is denoted by the letter of alphabet “H”, Boron is denoted by the letter of alphabet “B”, etc. Here these are the examples that use one letter but there are other elements that use more than 1 letter as the symbol. For example, the Chlorine is represented by the Cl.

8 0

1 year ago

Complete combustion of a 0.600-g sample of a compound in a bomb calorimeter releases 24.0 kJ of heat. The bomb calorimeter has a

JulijaS [17]

Answer : The correct option is, $30.9^oC$

Explanation :

Formula used :

$q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

where,

$q$ = heat released = 24 KJ

$m$ = mass of bomb calorimeter = 1.30 Kg

$c$ = specific heat = $3.41J/g^oC$

$T_{final}$ = final temperature = ?

$T_{initial}$ = initial temperature = $25.5^oC$

Now put all the given values in the above formula, we get the final temperature of the calorimeter.

$q=m\times c\times (T_{final}-T_{initial})$

$24KJ=1.30Kg\times 3.41J/g^oC\times (T_{final}-25.5)^oC$

$T_{final}=30.9^oC$

Therefore, the final temperature of the calorimeter is, $30.9^oC$

5 0

2 years ago

Read 2 more answers

How many moles of O2 should be supplied to burn 1 mol of C3H8 (propane) molecules in a camping stove

Shkiper50 [21]

The combustion of any hydrocarbon yields water and carbon dioxide. We will now construct a balanced equation:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

Each mole of propane requires 5 moles of oxygen.

4 0

1 year ago

Which gas tank will empty first? acetylene (C2H2) oxygen (O2)

Monica [59]

The answer is oxygen. (02)

4 0

2 years ago

Read 2 more answers

The concentration of C29H60 in summer rainwater is 34 ppb. Find the molarity of this compound in nanomoles per liter (nM).

Naya [18.7K]

Answer: The concentration of C29H60 in nM per liter is 83,33 nM/liter

Explanation: Let's start from the ppb definition: ppb means parts per billion. In terms of concentracion measuring this means micrograms of solute per liter of solution.

The algebraic expression would be:

<em>ppb [=] micrograms of compound/liter of solution</em>

We can assume that the solvent is water. The solute is dissolved in water and both create the C29H60 solution.

For the exercise we have 34 ppb of C29H60, that means 34 micrograms of C29H60 in one liter of solution. So, since now, we have to convert the units from the initial data to the required answer.

The respective procedure is in a attached file.

5 0

1 year ago