Answer:- 38.2 g.
Solution:- The equation used for solving this type of calorimetry problems is:
where, q is the heat energy, m is mass, c is specific heat and delta T is the change in temperature.
Water temperature is increasing from 14.5 degree C to 50.0 degree C.
= 35.5 degree C
q is given as 5680 J and specific heat value is .
The equation could be rearranged for m as:
Let's plug in the values in it:
m = 38.2 g
So, the mass of water in the kettle is 38.2 g.
Answer:
Explanation:
Hello.
In this case, since no information about the reacting hydrogen is given, we can assume that it completely react with the 28.0 g of acetylene to yield ethane. In such a way, via the 1:1 mole ratio between acetylene (molar mass = 26 g/mol) and ethane (molar mass = 30 g/mol), we compute the yielded grams, or the theoretical yield of ethane as shown below:
Hence, by knowing that the percent yield is computed via the actual yield (24.5 g) over the theoretical yield, we obtain:
Best regards.