answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
fenix001 [56]
1 year ago
15

The empirical formula for a compound is CH2. If n is a whole number, which shows a correct relationship between the molecular fo

rmula and the empirical formula?
Chemistry
2 answers:
Dima020 [189]1 year ago
6 0

Answer : The correct relationship between the molecular formula and the empirical formula is, \text{molecular mass}=n\times \text{empirical mass}

Explanation :

Empirical formula : It is the simplest form of the chemical formula which depicts the whole number of atoms of each element present in the compound.  

Molecular formula : it is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

n=\frac{\text{molecular mass}}{\text{empirical mass}}

As we are given that the empirical formula of a compound is CH_2.

\text{molecular mass}=n\times \text{empirical mass}

Thus, the molecular formula will be, (CH_2)_n

hjlf1 year ago
3 0
Molecular formula = empirical formula * n
You might be interested in
Plseas help Calculate the amount of moles in 57.6 Liters of Carbon Dioxide.
slavikrds [6]
Convert 57.6 L to dm3 and divide it by 24
8 0
1 year ago
One of the emission spectral lines for Be31 has a wavelength of 253.4 nm for an electronic transition that begins in the state w
max2010maxim [7]

Explanation:

The given data is as follows.

   \lambda = 253.4 nm = 253.4 \times 10^{-9}m      (as 1 nm = 10^{-9})

            n_{1} = 5,        n_{2} = ?

Relation between energy and wavelength is as follows.

                    E = \frac{hc}{\lambda}

                       = \frac{6.626 \times 10^{-34} Js \times 3 \times 10^{8} m/s}{253.4 \times 10^{-9}}

                       = 0.0784 \times 10^{-17} J

                       = 7.84 \times 10^{-19} J

Hence, energy released is 7.84 \times 10^{-19} J.

Also, we known that change in energy will be as follows.

     \Delta E = -2.178 \times (Z)^{2}[\frac{1}{n^{2}_{2}} - \frac{1}{n^{2}_{1}}

where, Z = atomic number of the given element

 7.84 \times 10^{-19} J = -2.178 \times (4)^{2}[\frac{1}{n^{2}_{2}} - \frac{1}{(5)^{2}}

    \frac{7.84 \times 10^{-19} J}{34.848} = \frac{1}{n^{2}_{2}} - \frac{1}{(5)^{2}}

      0.02 + 0.04 = \frac{1}{n^{2}_{1}}

                      n_{1} = \sqrt{\frac{1}{0.06}}

                          = 4

Thus, we can conclude that the principal quantum number of the lower-energy state corresponding to this emission is n = 4.

4 0
1 year ago
Consider the following voltaic cell. Identify the anode and cathode, and indicate the direction of Na ion and NO3- ion flow from
levacccp [35]

Answer:

Fe is the anode and Sn is the cathode; NO3- ions flow into half-cell compartment (A) and Na ions flow into half-cell compartment (B).

Explanation:

The purpose of a salt bridge in a voltaic cell is not to move electrons from the electrolyte, it's main function is the maintenance of charge balance between the half cells .The electrons flow from the anode to the cathode.

The iron half cell which has a higher reduction potential serves as anode. Iron atoms give up electrons to form positive ions according to the equation;

Fe(s)-----> Fe^2+(aq) + 2e

Hence there will be an excess of positive ions in the anode (compartment A). NO3^- ions from the salt bridge will migrate towards this compartment to ensure charge balance.

Similarly, in compartment B(cathode) Sn^2+ ions will accept two electrons according to the reaction;

Sn^2+(aq) + 2e ------> Sn(s)

This reaction causes a depletion of positive ions in compartment B, hence Na^+ from the salt bridge move towards this compartment to ensure charge balance.

4 0
1 year ago
Liquid nitrogen has a density of 0.807 g/ml at –195.8 °c. if 1.00 l of n2(l) is allowed to warm to 25°c at a pressure of 1.00 at
Flauer [41]
Step 1: Change density from g/mL to g/L;

                                  0.807 g/mL  =  807 g/L

Step 2: Find Moles of N₂;
As,
             Density  =  Mass / Volume
Or,
             Mass  =  Density × Volume

Putting Values,

            Mass  =  807 g/L × 1 L

            Mass  =  807 g
Also,
            Moles  =  Mass / M.mass

Putting values,

            Moles  =  807 g / 28 g.mol⁻¹

            Moles  =  28.82 moles

Step 3: Apply Ideal Gas Equation to Find Volume of gas occupied,

As,
                        P V  =  n R T

                            V  =  n R T / P
Putting Values, remember! don't forget to change temperatue into Kelvin (25 °C + 273 = 298 K)

                 V  =  (28.82 mol × 0.08206 atm.L.mol⁻¹.K⁻¹ × 298 K) ÷ 1 atm

                 V  =  704.76 L
8 0
1 year ago
Enough water is added to 50.0 mL of a 0.660 M NaOH solution in order to bring the total volume to 450.0 mL. What is the molarity
g100num [7]

Answer:

0.073 M

Explanation:

M1*V1 = M2*V2

M1 = 0.660 M

V1 = 50.0 mL

V2 = 450.0 mL

0.660M * 50.0 mL = M2*450.0 mL

M2 = 0.660M*50.0/450.0 = 0.073 M

5 0
2 years ago
Other questions:
  • Which of the following is the SI unit used to measure temperature? a. kilogram b. liter c. meter d. Kelvin Please select the bes
    13·2 answers
  • The percent composition by mass of a compound is 76.0% c, 12.8% h, and 11.2% o. the molar mass of this compound is 284.5 g/mol.
    14·1 answer
  • How many d electrons (n of dn) are in the central metal ion in the species below? (a) [ru(nh3)5cl]so4 6 d electrons (b) na2[os(c
    8·2 answers
  • The normal boiling point of c2cl3f3 is 47.6°c and its molar enthalpy of vaporization is 27.49 kj/mol. what is the change in entr
    7·1 answer
  • Recall that your hypothesis is that these values are the fraction of atoms that are still radioactive after n half-life cycles.
    15·2 answers
  • How many grams of nitrogen are in a sample of Al(NO3)3 that contains 364.0 g of aluminum? Answer: ________ grams of nitrogen.
    14·1 answer
  • Suppose you have exactly 1 cup (237 g) of hot (100.0 °C) brewed tea in an insulated mug and that you add to it 2.50 × 10² g of i
    15·1 answer
  • What is the dominant element attached to the carbon backbone
    12·1 answer
  • Aluminum metal reacts with aqueous cobalt(II) nitrate to form aqueous aluminum nitrate and cobalt metal. What is the stoichiomet
    8·1 answer
  • Identify the factors that directly favor the unloading of oxygen from hemoglobin in the blood near metabolically active tissues.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!