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2 years ago

A piece of sodium metal can be described as

1 answer:

8 0

<span>A piece of sodium metal can be described as a soft silvery white metal that is highly reactive and can sometimes cause explosions. This is the reason why it doesn't occur naturally as an isolated metal. Instead, different sodium containing compounds undergo different processes to isolate the sodium metal.</span>

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What is the percent by mass of sulfur in sulfur dioxide?a.32b.33c.50d.67?

-BARSIC- [3]

Molar mass of sulfur dioxide (SO2) is 64.066g/mol
molar mass of sulfur is 32.065 g/mol
thus, (32.065/64.066 )x100=50%

7 0

2 years ago

a compound is found to have 46.67% nitrogen, 6.70% hydrogen, 19.98% carbon and 26.65% oxygen, what is the empirical formula?

uranmaximum [27]

Search up “Chemistry, how to do empirical formulas” a guy named Tyler Dewitt is really good at explaining

4 0

2 years ago

A sample of krypton has a volume of 6.00 L, and the pressure is 0.960 atm. If the final temperature is 55.0°C, the final volume

MissTica

193.38 K was the initial temperature of the krypton.

Explanation:

Data given:

Initial volume of the krypton gas = 6 litres

initial pressure of the krypton gas = 0.960 atm

initial temperature of the krypton gas = ?

final volume of the krypton gas = 7.70 litres

final pressure of the Krypton gas = 1.25 atm

final temperature of the krypton gas = 55 degrees or 273.25+55 = 323.15 K

Applying the Combined Gas Laws:

$\frac{P1V1}{T1} = \frac{P2V2}{T2}$

Rearranging the equation:

T1 = $\frac{P1V1T2}{P2V2}$

Putting the value in the equation:

T1 = $\frac{0.960 X 6 X 323.15}{1.25 X 7.70}$

T1 = 193.38 K

Initial temperature of the krypton gas is 193.78 K

5 0

2 years ago

Suppose a layer of oil is on the top of a beaker of water. Water in many oils is slightly soluble, so its concentration is so lo

rodikova [14]

Explanation:

It is given that energy to transfer one water molecule is $2.208 \times 10^{-20}$ J/molecule

As it is known that in 1 mole there are $6.022 \times 10^{23}$ atoms.

So, energy in 1 mole = $2.208 \times 10^{-20} \times 6.022 \times 10^{23}$ J/mol

= 13.3 kJ/mol

As, $log \frac{k_{2}}{k_{1}} = \frac{E_{a}}{2.303 \times 8.314 atm L/mol K} \times \frac{T_{2} - T_{1}}{T_{1}T_{2}}$

Putting the given values in the above formula as follows.

$log \frac{k_{2}}{k_{1}} = \frac{E_{a}}{2.303 \times 8.314 atm L/mol K} \times \frac{T_{2} - T_{1}}{T_{1}T_{2}}$

$log \frac{k_{2}}{k_{1}} = \frac{13.3 kJ/mol}{2.303 \times 8.314 atm L/mol K} \times \frac{293 K - 283 K}{283K \times 293 K}$

$log \frac{k_{2}}{k_{1}}$ = 0.08377

$\frac{k_{2}}{k_{1}}$ = 1.213 = $\frac{Concentration_{2}}{Concentration_{1}}$

$Concentration_{2}$ = $1.213 \times Concentration_{1}$

= $1.213 \times 9 \times 10^{-4}$

= $10.915 \times 10^{-4}$ water molecules per oil molecule

Thus, we can conclude that the equilibrium concentration at 293 K, assuming that nothing else changes is $10.915 \times 10^{-4}$ .

4 0

2 years ago

In the compound k[co(c2o4)2(h2o)2] (where c2o42– = oxalate) the oxidation number and coordination number of cobalt are, respecti

ehidna [41]

Let's Assign Symbols to molecules like,

C₂O₄ = X
and
H₂O = Y
Then,
K [ Co (X)₂ (Y)₂ ]

As, Potassium (K) has a O.N = +1

To neutralize, the coordination sphere must have -1 oxidation number.
So,
[ Co (X)₂ (Y)₂ ] = -1
As,
O.N of X = -2
Then
O.N of (X)₂ = -4

Also,
O.N of H₂O is zero as it is neutral, So,

[Co - 4 + 0 ] = -1
Or,
Co = -1 + 4

Co = +3

Result:
Oxidation Number of Coordination Sphere is -1 and Oxidation Number of Cu is +3.

6 0

2 years ago

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