What is the simplest formula of a compound if a sample of the compound contains 0.221 mol X, 0.442 mol Y, and 0.884 mol Z? chemP
2 answers:
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Answer:
[Ca⁺²] = 0.0123 M
1234 ppm of CaCO₃
Explanation:
Ca(In)²⁺ + EDTA ⟶ Ca(EDTA)²⁺ + In
To solve this problem we need to keep in mind the definition of Molarity (moles/L) and parts per million (mg CaCO₃ / L water). First we <u>calculate the moles of EDTA</u>:
- 0.0450 M * 13.70 mL = 0.6165 mmol EDTA
Looking at the reaction we see that one mol of EDTA reacts with one mol of Ca(In)²⁺, so we have as well 0.6165 mmol Ca(In)²⁺ (which for this case is the same as Ca⁺²). We calculate the molarity of Ca⁺²:
- [Ca⁺²] = 0.6165 mmol / 50 mL = 0.0123 M
For calculating the concentration in ppm, we use the moles of Ca⁺² and the molecular weight of CaCO₃ (100.09 g/mol):
- 0.6165 mmol Ca⁺² *
* 100.09 mg/mmol = 61.70 mg CaCO₃
<u>That is the mass of CaCO₃ present in 50 mL</u> (or 0.05 L) of water, so the concentration in ppm is:
- 61.70 mg / 0.05 L = 1234 ppm
Answer:
Number of moles nitric acid in the cylinder is 400.539g/mol.
Explanation:
From the given,
Weight of empty gas cylinder = 30.01 g/mol
Number of moles nitric acid = =?
The mass of nitric acid in the cylinder =
Number of moles of nitric acid =
Therefore, number of moles nitric acid in the cylinder is 400.539g/mol.