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uranmaximum [27]
2 years ago
15

A researcher suspects that the pressure gauge on a 54.3-L gas cylinder containing nitric oxide is broken. An empty gas cylinder

weighs 90.0 lb. The weight of the partially full cylinder is 116.5 lb. This cylinder is located in a relatively chilly service hallway at 287 K. Follow the steps below to use the compressibility charts to estimate the pressure of the gas and the reading that the pressure gauge should have. How many moles of nitric oxide, NO, are in the cylinder?
Chemistry
1 answer:
mixer [17]2 years ago
3 0

Answer:

Number of moles nitric acid in the cylinder is 400.539g/mol.

Explanation:

From the given,

Weight of empty gas cylinder W_{1}= 90.0 lb= 40823.3 gramsWeight of full cylinder[tex]W_{2} = 116.5 lb= 52843.511 gramsThe critical temperature = 287 KThe critical pressure 54.3 LMolar mass of nitric acid = [tex]M_{NO} = 30.01 g/mol

Number of moles nitric acid = n_{NO} =?

The mass of nitric acid in the cylinder = W_{NO}=W_{2}-W_{1}

=52843.511-40823.3 =12,020.2g

Number of moles of nitric acid =

\frac{Given\,mass}{Molar\,mass}=\frac{12,020.2}{30}=400.539g/mol

Therefore, number of moles nitric acid in the cylinder is 400.539g/mol.

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recheck Fusion reactions power the in space. Humans currently use fusion in , but researchers are seeking more applications.
quester [9]

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4 0
2 years ago
Some instant cold packs contain ammonium nitrate and a separate pouch of water. When the pack is activated by squeezing to break
lubasha [3.4K]

Answer:

T_f=-7.81^0C

Explanation:

Hello,

a) In this case, since the heat associated with the dissolution of ammonium nitrate is positive, such reaction is endothermic as it absorbs heat.

b) Now, for computing the temperature once the dissolution is done, we apply (considering that it is a cooling process):

T_f=T_0-\frac{\Delta H}{mCp}

Nonetheless, we should first compute the moles of the mixture as:

n_{mix}=135.0gH_2O*\frac{1molH_2O}{18gH_2O}+50.0gNH_4NO_3*\frac{1molNH_4NO_3}{80gNH_4NO_3}=8.125mol

Thus, the total absorbed heat is:

\Delta H=25.4kJ/mol*8.125mol=206.375kJ

Now, the temperature is:

T_f=25.0^0C-\frac{25.4kJ}{(135.0+50.0)g*4.184x10^{-3}kJ/g^0C} \\\\T_f=-7.81^0C

Best regards.

3 0
2 years ago
Which has not been suggested as a reasonably practical way to store large amounts of hydrogen in relatively small spaces for its
Yakvenalex [24]

Answer: A. Liquefy hydrogen under pressure and store it much as we do with liquefied natural gas today.

Explanation:

Current Hydrogen storage methods fall into one of two technologies;

  1. <em>physical storage</em> where compressed hydrogen gas is stored under pressure or as a liquid; and
  2. <em>chemical storage</em>, where the hydrogen is bonded with another material to form a hydride and released through a chemical reaction.

Physical storage solutions are commonly used technologies but are problematic when looking at using hydrogen to fuel vehicles. Compressed hydrogen gas needs to be stored under high pressure and  requires large and heavy tanks. Also, liquid hydrogen boils at -253°C (-423°F) so it needs to be stored cryogenically with heavy insulation and actually contains less hydrogen compared with the same volume of gasoline.  

Chemical storage methods allow hydrogen to be stored at much lower pressures and offer high storage performance due to the strong binding of hydrogen and the high storage densities. They also occupy relatively smaller spaces than either compressed hydrogen gas or liquified hydrogen. A large number of chemical storage systems are under investigation, which involve hydrolysis reactions, hydrogenation/dehydrogenation reactions, ammonia borane and other boron hydrides, ammonia, and alane etc.

Other practical storage methods being researched that focuses on storing hydrogen as a lightweight, compact energy carrier for mobile applications include;

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5 0
2 years ago
How many moles are equal to 5.82 x 10^23 atoms of tungsten (w)
fiasKO [112]

Answer:

0.97 mole

Explanation:

1 mole will give 6.02×10^23 atoms

Xmole of tungsten will give 5.82×10^23 atom of tungsten

X= 5.82×10^23/ 6.02×10^23

X = 0.97 moles of tungsten

6 0
2 years ago
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