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Assoli18 [71]
2 years ago
10

A race car is driven by a professional driver at 99 . What is this speed in and ? 1 mile = 1.61 kilometers 1 hour = 60 minutes E

xpress the answers to the correct number of significant figures. The speed is equivalent to , or .
Chemistry
1 answer:
slavikrds [6]2 years ago
4 0

Answer: The speed is equivalent to <u>159.39 kilometers per hour </u>or <u>2.65 kilometers per minute.</u>

Explanation:

Given, The speed of a race car = 99 miles/ hour

To convert the speed into  kilometers per hour and kilometers per minute

Since   1 mile = 1.61 kilometers

So, Speed of car = (99 ) x (1.61 )

= 159.39 kilometers per hour.

Also, 1 hour = 60 minutes

Then, Speed of car = (159.39) ÷60

= 2.6565≈2.65 kilometer per minute.

Hence, the speed is equivalent to <u>159.39 kilometers per hour </u>or <u>2.65 kilometers per minute.</u>

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Jesse travels 3.0 meters east and then turns and travels 4.0 meters north. The trip requires 35 seconds. What is his velocity? 0
melisa1 [442]
Displacement = √(3² + 4²)
Displacement = 5 meters north east

Velocity = displacement / time
Velocity = 5 / 35
Velocity = 0.14 m/s northeast
6 0
1 year ago
Read 2 more answers
If a hazardous bottle is labeled 20.2 percent by mass Hydrochloric Acid, HCl, with a density of 1.096 g/mL, calculate the molari
SIZIF [17.4K]

Answer:6M

Explanation:

From Co= 10pd/M

Where Co= molar concentration of raw acid

p= percentage by mass of raw acid=20%

d= density of acid=1.096g/cm3

M= molar mass of acid=36.5

Co= 10×20×1.096/36.5=6M

5 0
2 years ago
A solution contains cr3+ ions. the addition of 0.063 l of 1.50 m naf solution was needed to completely precipitate the chromium
steposvetlana [31]

Cr{3+} + 3 NaF → CrF3 + 3 Na{+} <span>

First calculate the total mols of NaF. 

(0.063 L) x (1.50 mol/L NaF) = 0.0945 mol NaF total </span>

 

Using stoichiometric ratio:

<span>0.0945 mol NaF * (1 mol Cr3+ / 3 mol NaF) * (51.9961 g Cr3+/mol) = 1.6379 g Cr3+</span>
6 0
2 years ago
According to the reaction below, how many moles of Ba3(PO4)2(s) can be produced from 115 mL of 0.218 M BaCl2(aq)? Assume that th
Anna71 [15]

Answer:

0.01125 moles of Ba_3(PO_4)_2(s) can be produced from 115 mL of 0.218 M BaCl_2(aq).

Explanation:

Moles of BaCl_2 = n

Volume of the solution = 115 mL = 0.115 L ( 1 mL=0.001 L)

Molarity of the BaCl_2 solution = 0.218 M

0.218 M=\frac{n}{0.115 L}

n = 0.218\times 0.115 L=0.03379 mol

3 BaCl_2(aq) + 2Na_3PO_4(aq)\rightarrow Ba_3(PO_4)_2(s) + 6NaCl(aq)

According to reaction, 3 moles BaCl_2 gives 1 mole of Ba_3(PO_4)_2 .Then 0.03379 moles of BaCl_2 will give :

0.03379 mol\times \frac{1}{3}=0.01126 mol

0.01125 moles of Ba_3(PO_4)_2(s) can be produced from 115 mL of 0.218 M BaCl_2(aq).

3 0
2 years ago
Read 2 more answers
Write two chemical formulae showing the steps involved when a metal combined with a radical
nirvana33 [79]

Answer:

An example of a metal with an organic radical is: Pentamethylcyclopentadiene, which is the union between Zinc and an organic compound, where in order to obtain it there is a release of dihydrogen.

Another example is lead tetraethyl, it is a compound for industrial use, it is dangerous for the human body, toxic and can be used as fuel.

Explanation:

In radical chemistry a chemical species is called both organic and inorganic, which one of the most used examples is methyl, where it is a chemical structure that has one carbon and 4 hydrogens attached to this central carbon.

These chemical compounds when united with metals, release one of the unions that they have with hydrogens, it is because in reactions they release hydrogens.

4 0
1 year ago
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