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2 years ago

Write two chemical formulae showing the steps involved when a metal combined with a radical

Chemistry

1 answer:

nirvana33 [79]2 years ago

4 0

Answer:

An example of a metal with an organic radical is: Pentamethylcyclopentadiene, which is the union between Zinc and an organic compound, where in order to obtain it there is a release of dihydrogen.

Another example is lead tetraethyl, it is a compound for industrial use, it is dangerous for the human body, toxic and can be used as fuel.

Explanation:

In radical chemistry a chemical species is called both organic and inorganic, which one of the most used examples is methyl, where it is a chemical structure that has one carbon and 4 hydrogens attached to this central carbon.

These chemical compounds when united with metals, release one of the unions that they have with hydrogens, it is because in reactions they release hydrogens.

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Which of the following lists describes characteristics of a base?

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Answer:

bitter taste low ph and slipery

Explanation:

if its sour or dissolves metal it is an acid

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2 years ago

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The heat of combustion of propane, C3H8, is 2220 kJ/mol. The specific heat of copper is 0.385 J/g°C. How many grams of propane m

Mamont248 [21]

Answer:

Explanation:

q = (mass) (temp change) (specific heat)

q = (10000 g) (40 °C) (0.385 J/g⋅°C) = 154000 J = 154 kJ

154 kJ / 2220 kJ/mol = 0.069369369 mol

0.069369369 mol times 44.0962 g/mol = 3.06 g (to three sig figs)

answer choice 4

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2 years ago

Nitrosyl bromide decomposes according to the chemical equation below. 2NOBr(g) 2NO(g) + Br2(g) 1.00 atm of NOBr is sealed in a f

Andrew [12]

Given :

2NOBr(g) - -> 2NO(g) + Br2(g)

Initial pressure of NOBr , 1 atm .

At equilibrium, the partial pressure of NOBr is 0.82 atm.

To Find :

The equilibrium constant for the reaction .

Solution :

2NOBr(g) - -> 2NO(g) + Br2(g)

t=0 s 1 atm 0 0

$t=t_{eqb}$ 1( 1-2x) 2x x

So ,

$1-2x=0.82\\\\x=0.09$

At equilibrium :

$K_{eq}=\dfrac{[NO]^2[br_2]}{[NOBr]^2}\\\\K_{eq}=\dfrac{0.18^2\times 0.9}{0.82^2}\\\\K_{eq}=0.043\ atm$

Hence , this is the required solution .

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2 years ago

4. Consider the following statement made in Chapter 4 of the text: "... consider that if the

AveGali [126]

The claim: "If the nucleus were the size of a grape, the electrons would be one mile away on average" is reasonably accurate because the ratios between the nucleus's sizes and the distances (between electrons and nucleus) for the two given examples are in the same order of magnitude.

To know if the claim is accurate we need to calculate the ratio of the size of the nucleus (the same as a grape) and the distance between the electrons and the nucleus for example 1 (r₁):

$r_{1} = \frac{s_{1}}{d_{1}}$ (1)

and to compare it with the ratio of the size and the distance given in example 2 (r₂):

$r_{2} = \frac{s_{2}}{d_{2}}$ (2)

Where:

s₁: is the size of the nucleus (like the size of a grape)

d₁: is the distance between electrons and nucleus of example 1 = 1 mile

s₂: is the average diameter of the nucleus = 10⁻¹³ cm

d₂: is the average distance between electrons and nucleus of example 2 = 10⁻⁸ cm

Assuming that the diameter of a grape is 3 cm (in a spherical way), the ratio of the first example is (eq 1):

$r_{1} = \frac{3 cm}{1 mi*\frac{160934 cm}{1 mi}} = 1.86 \cdot 10^{-5}$

Now, the ratio of the second example is (eq 2):

$r_{2} = \frac{10^{-13} cm}{10^{-8} cm} = 1.00 \cdot 10^{-5}$

Since r₁ and r₂ are in the same order of magnitude (10⁻⁵), we can conclude that the given claim is reasonably accurate.

You can learn more about the nucleus of an atom here: brainly.com/question/10658589?referrer=searchResults

I hope it helps you!

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2 years ago

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creativ13 [48]

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2 years ago

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