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inn [45]
2 years ago
6

Nitrosyl bromide decomposes according to the chemical equation below. 2NOBr(g) 2NO(g) + Br2(g) 1.00 atm of NOBr is sealed in a f

lask. At equilibrium, the partial pressure of NOBr is 0.82 atm. What is the equilibrium constant for the reaction?
Chemistry
1 answer:
Andrew [12]2 years ago
3 0

Given :

2NOBr(g) - -> 2NO(g) + Br2(g)

Initial pressure of NOBr , 1 atm .

At equilibrium, the partial pressure of NOBr is 0.82 atm.

To Find :

The equilibrium constant for the reaction .

Solution :

             2NOBr(g) - -> 2NO(g) + Br2(g)

t=0 s           1 atm                 0             0

t=t_{eqb}       1( 1-2x)               2x           x

So ,

1-2x=0.82\\\\x=0.09

At equilibrium :

K_{eq}=\dfrac{[NO]^2[br_2]}{[NOBr]^2}\\\\K_{eq}=\dfrac{0.18^2\times 0.9}{0.82^2}\\\\K_{eq}=0.043\ atm

Hence , this is the required solution .

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A 0.500 g sample of tin (Sn) is reacted with oxygen to give 0.534 g of product. What is the empirical formula of the oxide?
REY [17]

Answer:

Sn_2O

Explanation:

Hello,

In this case, given that the mass of the product is 0.534 g, we can infer that the percent composition of tin is:

\%Sn=\frac{0.500g}{0.534g}*100\%\\ \\\%Sn=93.6\%

Therefore, the percent composition of oxygen is 6.4% for a 100% in total. Thus, with such percents we compute the moles of each element in the oxide:

n_{Sn}=93.6gSn*\frac{1molSn}{118.8gSn} =0.788molSn\\\\n_O=6.4gO*\frac{1molO}{16gO}=0.4molO

In such a way, for finding the smallest whole number we divide the moles of both tin and oxygen by the moles of oxygen as the smallest moles:

Sn:\frac{0.788}{0.4}=2\\ \\O:\frac{0.4}{0.4}=1

Therefore, the empirical formula is:

Sn_2O

Best regards.

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2 years ago
The actual size of a wood louse is 0.4mm but Robert drew his 5mm. What is the magnification?
melomori [17]

Answer:

Magnification is the number of times larger an image is compared with the real size of the object.

Magnification = Image / Actual  = 5/0.4 =12.5

Explanation:

3 0
2 years ago
Which process is based on repulsion of oil and water?
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Answer:

We can seprate oil and water by the process of seprating funnel

5 0
2 years ago
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Hydrochloric acid (75.0 mL of 0.250 M) is added to 225.0 mL of 0.0550 M Ba(OH)2 solution. What is the concentration of the exces
Shalnov [3]

Answer:  The concentration of excess [OH^-] in solution is 0.017 M.

Explanation:

1. Molarity=\frac{moles}{\text {Volume in L}}

moles of HCl=Molarity\times {\text {Volume in L}}=0.250\times 0.075=0.019moles

1 mole of HCl give = 1 mole of H^+

Thus 0.019 moles of HCl give = 0.019 mole of H^+

2. moles of Ba(OH)_2=Molarity\times {\text {Volume in L}}=0.0550\times 0.225=0.012moles

According to stoichiometry:

1 mole of Ba(OH)_2 gives = 2 moles of OH^-

Thus 0.012 moles of Ba(OH)_2 give = 2 \times 0.012=0.024 moles of OH^-

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As 1 mole of H^+ neutralize 1 mole of OH^-

0.019 mole of H^+ will neutralize 0.019 mole of OH^-

Thus (0.024-0.019)= 0.005 moles of OH^- will be left.

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4 0
2 years ago
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Which of the following reactions are possible if sodium is more reactive than aluminum, 3 iron, and lead?
Deffense [45]

Answer:

Reaction I: Sodium + Aluminum chloride →Sodium chloride + Aluminum

Explanation:

Sodium being more reactive means that it will take the place of aluminium in whats called a displacement reaction and form.

Sodium chloride + Aluminum

8 0
2 years ago
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