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pogonyaev
2 years ago
7

A sample of ch4o with a mass of 32.0 g contains ________ molecules of ch4o.

Chemistry
1 answer:
ValentinkaMS [17]2 years ago
3 0
6.02 times 10 to the 23 power, which is Avogadros number 
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What is the molarity of an h3po4 solution if 15.0 ml is completely neutralized by 38.5 ml of 0.150m naoh?
just olya [345]
The molarity  of H3PO4   solution  if   15.0  ml  is completely    neutralized by  38.5  ml  of   0.15m naoh  is  calculated   as  follows
find  moles of  NaOH  used  =   molarity  x  volume
=  38.5  x  0.15  =    5.775  moles

write   the    reacting  equation
 3NaOH  + H3PO4  =  Na3PO4  + 3H2O

from  the  equation the  reacting   ratio  between  NaOH  to  H3Po4   which  is 3:1  the  moles  of  H3PO4    is  therefore  =  5.775/3  =  1.925  moles

molarity of  H3PO4  is therefore  =  moles  /volume
=  1.925/15  =  0.128 M
4 0
2 years ago
Read 2 more answers
Two students are given different samples of a substance and are instructed to determine the properties of the substance.
Hunter-Best [27]

The complete question is given below:

Two students are given different samples of a substance and are instructed to determine the properties of the substance.  

Which statement describes a property that will be the same for both students?

A. color because it is an extensive property

B. mass because it is an extensive property

C. boiling point because it is an intensive property

D. volume because it is an intensive property .

ANSWER

The correct option is C.

The physical properties of substances are divided into two, intensive and extensive properties.

Intensive properties refers to those features of a substance that do not depend on the quantity of the material that is available. Whether the sample available is big or small, the intensive properties remain the same. Examples of intensive properties are:  melting point, boiling point, refractive index, hardness, density color, etc. This question is asking us to look for an intensive property.

Extensive properties refers to those characteristics of a substance that depend on the amount of substance present. Examples of these properties are: mass, volume, size, weight, length, etc.

From the options given, option A is wrong because color is not an extensive property, it is intensive. Option B is wrong because the mass depend on the amount of sample given and the same thing apply to option D.

The correct option is C,  because no matter the quantity of that substance that you have, the boiling point will always remains the same.  

6 0
2 years ago
What is the oxidation state of selenium in SeO3?​
ra1l [238]

Answer: The oxidation state of selenium in SeO3 is +6

Explanation:

SeO3 is the chemical formula for selenium trioxide.

- The oxidation state of SeO3 = 0 (since it is stable and with no charge)

- the oxidation number of oxygen (O) IN SeO3 is -2

- the oxidation state of selenium in SeO3 = Z (let unknown value be Z)

Hence, SeO3 = 0

Z + (-2 x 3) = 0

Z + (-6) = 0

Z - 6 = 0

Z = 0 + 6

Z = +6

Thus, the oxidation state of selenium in SeO3 is +6

8 0
2 years ago
Determine the compound type for the following formulas: C12H22011 Mg(OH)2 H20 Cu3Zn2 Au <br>​
Scorpion4ik [409]

Answer:

C12H22O11  

✔ covalent

Mg(OH)2    

✔ Ionic

H2O    

✔ covalent

Cu3Zn2    

✔ metallic

Au      

✔ metallic

Explanation:

7 0
2 years ago
Read 2 more answers
A 2400.-gram sample of an aqueous solution contains 0.012 gram of nh3. What is the concentration of nh3 in the solution
Kryger [21]

Answer : The concentration of NH_3 in the solution is, 2.94\times 10^{-4}M

Explanation :

First we have to calculate the volume of aqueous solution that is water.

Density of water = 1.00 g/mL

Mass of water = 2400 g

\text{Volume of water}=\frac{Mass}{Density}=\frac{2400g}{1.00g/mL}=2400mL

Now we have to calculate the concentration of ammonia solution.

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

\text{Molarity}=\frac{\text{Mass of }NH_3\times 1000}{\text{Molar mass of }NH_3\times \text{Volume of solution (in mL)}}

Molar mass of NH_3 = 17 g/mole

Now put all the given values in this formula, we get:

\text{Molarity}=\frac{0.012g\times 1000}{17g/mole\times 2400mL}=3.12mole/L=2.94\times 10^{-4}M

Therefore, the concentration of NH_3 in the solution is, 2.94\times 10^{-4}M

7 0
2 years ago
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