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Ghella [55]
2 years ago
11

Which compounds will most likely dissociate when dissolved in water? select all that apply

Chemistry
2 answers:
scoundrel [369]2 years ago
4 0

 

The following compounds are soluble in water and will dissociate when dissolved in water.


A) barium hydroxide

B) ethanol  

C) glucose


D) silver nitrate  

E) dichloromethane


F) postassium chloride


The other compounds ethanol and glucose  are also soluble in water but do not dissociate when dissolved in water.

gulaghasi [49]2 years ago
3 0

Answer : The Correct Answer Is A , D , And F

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Which of these correctly defines the pOH of a solution? the log of the hydronium ion concentration the negative log of the hydro
Likurg_2 [28]

Answer : The correct option is, the negative log of the hydroxide ion concentration.

Explanation :

pOH : It is defined as the negative logarithm of hydroxide ion concentration. It is a measure of the alkalinity of the solution.

Formula used :

pOH=-log[OH^-]

[OH^-] is the concentration of OH^- ions.

When pOH is less than 7, the solution is alkaline.

When pOH is more than 7, the solution is acidic.

When pOH is equal to 7, the solution is neutral.

4 0
2 years ago
Read 2 more answers
A 0.216 g sample of an aluminium compound X reacts with an excess of water to produce a single hydrocarbon gas. This gas burns c
makkiz [27]
0.216g of aluminium compound X  react with an excess of water water to produce gas. this gas burn completely  in O2  to form H2O and 108cm^3of CO2 only . the volume of CO2 was measured at room temperature and pressure

0.108 / n  =  24 / 1 
n = 0.0045 mole ( CO2 >>0.0045 mole 
0.216 - 0.0045 = 0.2115
so Al =   0.2115 / 27  =>  0.0078 mole 
C = 0.0045 * 1000 => 4.5    and Al  = 0.0078 * 1000 = 7.8 

7 0
2 years ago
A student heats a sample of Copper (II) sulfate in a crucible and records the data shown in the table. What is the complete form
liberstina [14]

Explanation:

Copper (II) sulfate is usually present as a hydrous state, which is of the form CuSO4 * nH2O, where n is a whole number.

Mass of sample (CuSO4 * nH2O)

= 152.00g - 128.10g = 23.90g.

Mass of water loss during heating

= 152.00g - 147.60g = 4.40g.

Molar mass of H2O = 18g/mol

Moles of H2O in sample

= 4.40g / (18g/mol) = 0.244mol.

Mass of anhydrous sample (CuSO4)

= 23.90g - 4.40g = 19.50g

Molar mass of CuSO4 = 159.61g/mol

Moles of CuSO4 in sample

= 19.50g / (159.61g/mol) = 0.122mol.

Since mole ratio of CuSO4 to H2O

= 0.122mol : 0.244mol = 1:2, n = 2.

Hence we have CuSO4 * 2H2O.

6 0
2 years ago
Read 2 more answers
Suppose you are studying the K sp of K C l O 3 , which has a molar mass of 122.5 g/mol, at multiple temperatures. You dissolve 4
Ghella [55]

Answer:

The K sp Value is  K_{sp}=7.40

Explanation:

From the question we are told that

   The of KClO_3 is = 122.5 g/ mol

    The mass of KClO_3 dissolved is m_s = 4.0g

    The volume of solution is  V_s = 12mL = 12*10^{-3}L

The number of moles of KClO_3 is mathematically evaluated as

           No \ of  \ moles  \ = \frac{mass }{Molar \ mass}

Substituting values

                                  = \frac{4}{122.5}

                                  =0.0327\ moles

Generally concentration is mathematically represented as

         concentration = \frac{No \ of \ moles}{volume }

For KClO_3        

               Z= \frac{0.0327}{12*10^{-3}}

                              =2.72 \ mol/L

The dissociation reaction of KClO_3  is

         KClO_3 \ ----> K^{+}_{(aq)} + ClO_3^-_{(aq)}

The solubility product constant is mathematically represented as

                   K_{sp} = \frac{concentration of ionic product }{concentration of ionic reactant }

Since there is no ionic reactant we have

                  K_{sp} = [k^+] [ClO_3^-]

                          = Z^2

                          = 2.72^2

                          K_{sp}=7.40

                         

5 0
2 years ago
Read 2 more answers
Determine the velocity of a marble (m = 8.66 g) with a wavelength of 3.46 × 10-33m.a.45.2 m/sb.11.3 m/sc.22.1 m/sd.38.8 m/se.52.
Damm [24]

Answer:

Velocity = 22.11 m/s

Explanation:

Using the equation;

λ = h / mv;

where  

λ = wavelength ( 3.46 x 10^-33 )  

m = mass of the marble ( 8.66 g )  

v = velocity ( we gotta find out )  

h = planck's constant ( 6.626 * 10^-34 )  

Making v the subject of the formula;

V = h /mλ

  =(6.626 x 10^-34 ) / 0.00866 ( 3.46 x 10^-33 )  

  = 22.1135

≈ 22.11 m/s

6 0
2 years ago
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