Answer:
Explanation:
Pair 2.50g of O₂ and 2.50g of N₂
The atoms sample with the largest number of moles since the masses are the same would be the one with lowest molar mass according the the equation below:
Number of moles = 
Atomic mass of O = 16g and N = 14g
Molar mass of O₂ = 16 x 2 = 32gmol⁻¹
Molar mass of N₂ = 14 x 2 = 28gmol⁻¹
Number of moles of O₂ = 
= 0.078mole
Number of moles of N₂ = 
= 0.089mole
We see that N₂ has the largest number of moles
Answer: Option (c) is the correct answer.
Explanation:
A water molecule is made up of two hydrogen atoms and one oxygen atom. Due to the difference in electronegativity of hydrogen and oxygen, the electrons are pulled more towards oxygen atom.
As a result, a partial positive charge will develop on hydrogen atom and a partial negative charge will develop on oxygen atom.
Thus, we can conclude that adjacent water molecules interact through the electrical attraction between the hydrogen of one water molecule and the oxygen of another water molecule.
Answer:
0.467 kilograms of protein or carbohydrates
Explanation:
First, there is a need to understand that <em>1 kJ = 0.239 kCal</em>
Hence, 17 kJ = 17 x 0.239 = 4.063 kCal
The race requires 650.0 kCal/hr and has to last for 175 minutes.
175 minutes = 175/60 = 2.917 hrs
The total kCal requires for the race = 650 x 2.917 = 1,895.833 kCal
1 g of protein or carbohydrate food produces 17.0 kJ or 4.063 kCal of energy. Hence, the total g of protein or carbohydrate that will produce 1,895.833 kCal of energy would be;
1,895.833/4.063 = 466.609 g
<em>1 g = 0.001 kg</em>
466.609 g = 466.609 x 0.001 = 0.467 kg
<em>Hence, </em><em>0.467 </em><em>kilograms of proteins or carbohydrates must be consumed.</em>
The compound contains Carbon, Hydroxide and Oxide
1 mole of carbon iv oxide contains 44 g, out of which 12 g are carbon.
Therefore, 1.6004 g of CO2 will contain;
1.6004 ×12/44 = 0.4365 g of carbon
1 mole of water contains 18 g of which 2 g is hydrogen,
Therefore, 0.6551 g of H2O will hace ;
0.6551 × 2/18 = 0.0728 g of hydrogen.
The total mass of the compound is 0.8009 g,
Thus the mass of oxygen = 0.8009 -(0.4365 +0.0728)
= 0.2916 g
To get the empirical formula we first get the number of moles of each element;\
Carbon = 0.4365/12= 0.036375 moles
Hydrogen = 0.0728/1 = 0.0728 moles
Oxygen = 0.2916/16 = 0.018225 moles
Then, to get the smallest ratio we divide each with the smallest value;
Carbon : Hydrogen : Oxygen
= (0.036375/0.018225) : (0.0728/0.018225) : ( 0.018225/0.018225)
= 1.996 : 3.995 : 1
≈ 2 : 4 : 1
Therefore, the empirical formula is C2H4O
