All categories

2 years ago

Which of the following statements correctly relates mutations and survival rates of plants?

1 answer:

3 0

Answer is: Mutations sometimes improve the chances of survival for a plant.
Mutations are very important because they change variability in populations and in that way enable evolutionary change.
There are three types of mutations:
1) good or advantageous mutations - improve the chances of survival for a plant.
2) bad or deleterious - decrease the chances of survival for a plant.
3) neutral - not affect he chances of survival for a plant.

You might be interested in

An unopened, cold 2.00 L bottle of soda contains 46.0 mL of gas confined at a pressure of 1.30 atm at a temperature of 5.0oC. If

Katena32 [7]

Answer:

20.8mL

Explanation:

7 0

1 year ago

The piece of iron that miguel measured had a mass of 51.1 g and a volume of 6.63 cm 3 . what did miguel calculate to be the dens

likoan [24]

Given:
Mass, m = 51.1 g
Volume, V = 6.63 cm³

By definition,
Density = Mass/Volume
= (51.1 g)/(6.63 cm³)
= 7.7074 g/cm³

In SI units,
Density = (7.7074 g/cm³)*(10⁻³ kg/g)*(10² cm/m)³
= 7707.4 kg/m³

Answer: 7.707 g/cm³ or 7707.4 kg/m³

4 0

2 years ago

What mass of CaSO3 must have been present initially to produce 14.5 L of SO2 gas at a temperature of 12.5°C and a pressure of 1.

german

When the reaction equation is:

CaSO3(s) → CaO(s) + SO2(g)

we can see that the molar ratio between CaSO3 & SO2 is 1:1 so, we need to find first the moles SO2.

to get the moles of SO2 we are going to use the ideal gas equation:

PV = nRT

when P is the pressure = 1.1 atm

and V is the volume = 14.5 L

n is the moles' number (which we need to calculate)

R ideal gas constant = 0.0821

and T is the temperature in Kelvin = 12.5 + 273 = 285.5 K

so, by substitution:

1.1 * 14.5 L = n * 0.0821 * 285.5

∴ n = 1.1 * 14.5 / (0.0821*285.5)

= 0.68 moles SO2

∴ moles CaSO3 = 0.68 moles

so we can easily get the mass of CaSO3:

when mass = moles * molar mass

and we know that the molar mass of CaSO3= 40 + 32 + 16 * 3 = 120 g/mol

∴ mass = 0.68 moles* 120 g/mol = 81.6 g

7 0

2 years ago

a 75.0 liter canister contains 15.82 moles of argon at a pressure of 546.8 kilopascals. What is the temperature of the canister?

abruzzese [7]

Pressure of argon = 546.8 kPa

Conversion factor: 1 atm = 101.325 kPa

Pressure of argon = 546.8 kPa x 1 atm/101.325 kPa = 5.4 atm

Moles of argon = 15.82

Volume of argon = 75.0 L

According to Ideal gas law,

PV = nRT

where P is the pressure, V is the volume , n is the number of moles, R is the universal gas constant, and T is the temperature

T = PV/nR = (5.4 atm x 75.0 L) / (15.82 x 0.0821 L.atm.mol⁻¹K⁻¹)

T = 311.82 K

Hence the temperature of the canister is 311.82 K.

4 0

2 years ago

To help farmers and gardeners, commercial fertilizers have a big three-number "NPK" label on the bag that gives the amounts of t

Ludmilka [50]

Answer:

The number on the lag label should be 15.

Explanation:

It seems your question is incomplete, as it is lacking the working values. An internet search showed me the full question, you can see it in the attached picture.

Let's say we have 100 g of the fertilizer.

45 g are of ammonium phosphate ( (NH₄)₃PO₄ ), of which:

45 g (NH₄)₃PO₄ * $\frac{42 g N}{149g(NH_{4})_{3}PO_{4}}$ = 12.7 g are of Nitrogen.

(We used the molar mass of ammonium phosphate in the denominator and three times the molar mass of nitrogen in the numerator)

18 g are of calcium nitrate (Ca(NO₃)₂), of which:

16 g Ca(NO₃)₂ * $\frac{28gN}{164gCa(NO_{3})_{2}}$ = 2.73 g are of Nitrogen.

So in total there are (12.7+2.73) 15.43 g of Nitrogen in 100 g of the fertilizer. So the percent by mass of nitrogen is 15.43%.

Rounding to the nearest percent the answer is 15.

8 0

1 year ago