A 1.0 g sample of a cashew was burned in a calorimeter containing 1000. g of water, and the temperature of the water changed fro
1 answer:
Answer:
The correct answer is option C.
Explanation:
1.0 g sample of a cashew :
Heat released on combustion of 1.0 gram of cashew = -Q
We have mass of water = m = 1000 g
Specific heat of water = c = 4.184 J/g°C
ΔT = 30°C - 25°C = 5°C
Heat absorbed by the water : Q
Heat released on combustion of 1.0 gram of cashew is -20,920 J.
3.0 g sample of a marshmallows :
Heat released on combustion of 3.0 g sample of a marshmallows = -Q'
We have mass of water = m = 2000 g
Specific heat of water = c = 4.184 J/g°C
ΔT = 30°C - 25°C = 5°C
Heat absorbed by the water : Q'
Heat released on 3.0 g sample of a marshmallows= -Q' = -41,840 J
Heat released on 1.0 g sample of a marshmallows : q
Heat released on combustion of 1.0 gram of marshmallows -13,946.67 J.
-20,920 J. > -13,946.67 J
The combustion of 1.0 g of cashew releases more energy than the combustion of 1.0 g of marshmallow.
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Answer:
See picture for answer
Explanation:
First to all, an aldehyde is a carbonated chain with a Carbonile within it chain. It's call aldehyde basically because the C = O is always at the end of the chain. When the C = O is on another position of the chain, is called a ketone.
Now, in this exercise we have an aldehyde with 5 carbons, so the first carbon is the C = O. The remaining four carbon belong to the chain. however, we need to have a branched chain in this molecular formula.
If this the case, this means that the longest chain cannot have 5 carbons. It should have 4 carbons as the longest chain. The remaining carbon, would one branched.
In this case, we only have two possible ways to have an aldehyde with a branched chain, and 4 carbons at max. One methyl in position 2, and the other in position 3.
The remaining aldehyde with branched chain, cannot have 4 carbons as longest, it should have 3 carbons with longest chain and 2 carbons as radicals (In this case, methyl). In this way, we just have all the aldehyde with this formula and at least one branched chain. The other possible ways would be conformers or isomers of the first three.
See picture for the structures of these 3 aldehydes, and their names.}
Explanation:
It is known that efficiency is denoted by .
The given data is as follows.
= 0.82,
= (21 + 273) K = 294 K
= 200 kPa,
= 1000 kPa
Therefore, calculate the final temperature as follows.
0.82 =
= 1633 K
Final temperature in degree celsius =
=
Now, we will calculate the entropy as follows.
For 1 mole,
It is known that for the value of
= 0.028 kJ/mol.
Therefore, putting the given values into the above formula as follows.
=
= 0.0346 kJ/mol
or, = 34.6 J/mol (as 1 kJ = 1000 J)
Therefore, entropy change of ammonia is 34.6 J/mol.