You are asked to determine the mass of a piece of copper using its reported density, 8.96 g/ml, and a 150-ml graduated cylinder.
first, you add 105 ml of water to the graduated cylinder; then you place the piece of copper in the cylinder and record a volume of 137 ml. what is the mass of the copper reported with the correct number of significant figures?
2 answers:
The mass of the copper reported with the correct number of significant figures : 290 grams
<h3></h3><h3>Further explanation </h3>Density is a quantity derived from the mass and volume
Density is the ratio of mass per unit volume
The unit of density can be expressed in g / cm³ or kg / m³
Density formula:
ρ = density
m = mass
v = volume
A common example is the water density of 1 gr / cm³
A piece of copper using its reported density, 8.96 g/ml
Volume changes in the graduated cylinder indicate the volume of a piece of copper
initial volume = 105
final volume = 137
volume change = 137-105 = 32 ml
So the mass :
mass = 8.96 g/ml x 32 ml
mass = 286.72 gram
In multiplication and division of significant numbers, the final results look at the least number of significant numbers.
Because the number 32 on the multiplication above has 2 significant numbers, the result of multiplication must also have 2 significant numbers
So 286.72 gram round up become 290 (2 significant number)
<h3>Learn more </h3>
the mass of earth
the density of the fuel
A drop of acetone
Keywords: density, mass, volume, a block of osmium
Answer:- Mass of copper piece is 290 gram.
Solution:- We know that, mass = density * volume
density of copper is given as 8.96 gram per mL.
Volume of copper piece is the rise change in volume.
Volume of copper piece = 137 mL - 105 mL = 32 mL
Let's multiply the volume by density to calculate the mass of copper:
mass of copper =
mass of copper = 286.72 g
Volume has two significant figures, so if we round the mass to two significant figures then it becomes 290 g.
You might be interested in
Answer:
strength of hypericin in mixture = 0.42 %
Explanation:
given data
each lot = 100 g
active component hypericin = 0.3%, 0.7%, and 0.25%
solution
we get here percent strength o hypericin in the mixture that is
Hypericin contribution lot 1 = × 100
Hypericin contribution lot 1 = 0.3 g
and
Hypericin contribution lot 2 = × 100
Hypericin contribution lot 2 = 0.7 g
and
Hypericin contribution lot 3 = × 100
Hypericin contribution lot 3 = 0.25 g
so
total 300 g mixture of hypericin contain = 0.3 g + 0.7 g + 0.25 g
total 300 g mixture of hypericin = 1.25 g
so here percent strength o hypericin in mixture is
strength of hypericin in mixture = × 100
strength of hypericin in mixture = 0.42 %
Answer : The expected coordination number of NaBr is, 6.
Explanation :
Cation-anion radius ratio : It is defined as the ratio of the ionic radius of the cation to the ionic radius of the anion in a cation-anion compound.
This is represented by,
When the radius ratio is greater than 0.155, then the compound will be stable.
Now we have to determine the radius ration for NaBr.
Given:
Radius of cation, = 102 pm
Radius of cation, = 196 pm
As per question, the radius of cation-anion ratio is between 0.414-0.732. So, the coordination number of NaBr will be, 6.
The relation between radius ratio and coordination number are shown below.
Therefore, the expected coordination number of NaBr is, 6.
