Question

You are asked to determine the mass of a piece of copper using its reported density, 8.96 g/ml, and a 150-ml graduated cylinder. first, you add 105 ml of water to the graduated cylinder; then you place the piece of copper in the cylinder and record a volume of 137 ml. what is the mass of the copper reported with the correct number of significant figures?

Answer 1

The mass of the copper reported with the correct number of significant figures : 290 grams

Further explanation

Density is a quantity derived from the mass and volume

Density is the ratio of mass per unit volume

The unit of density can be expressed in g / cm³ or kg / m³

Density formula:

$\large{\boxed {\bold {\rho~=~ \frac {m} {V}}}}$

ρ = density

m = mass

v = volume

A common example is the water density of 1 gr / cm³

A piece of copper using its reported density, 8.96 g/ml

Volume changes in the graduated cylinder indicate the volume of a piece of copper

initial volume = 105

final volume = 137

volume change = 137-105 = 32 ml

So the mass :

$mass=\rho\:\times\:v$

mass = 8.96 g/ml x 32 ml

mass = 286.72 gram

In multiplication and division of significant numbers, the final results look at the least number of significant numbers.

Because the number 32 on the multiplication above has 2 significant numbers, the result of multiplication must also have 2 significant numbers

So  286.72 gram round up become 290 (2 significant number)

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Keywords: density, mass, volume, a block of osmium

Answer 2

Answer:- Mass of copper piece is 290 gram.

Solution:- We know that, mass = density * volume

density of copper is given as 8.96 gram per mL.

Volume of copper piece is the rise change in volume.

Volume of copper piece = 137 mL - 105 mL = 32 mL

Let's multiply the volume by density to calculate the mass of copper:

mass of copper = $32mL(\frac{8.96g}{mL})$

mass of copper = 286.72 g

Volume has two significant figures, so if we round the mass to two significant figures then it becomes 290 g.