Thermal energy will flow from an object high temperature to an object of low one. In this case, the thermal energy will flow from object B to object A.
To know the acidity of a
solution, we calculate the pH value. The formula for pH is given as:
<span>pH = - log [H+] where H+ must be in Molar</span>
We are given that H+ = 3.25 × 10-2 M
Therefore the pH is:
pH = - log [3.25 × 10-2]
pH = 1.488
Since pH is way below 7, therefore the solution
is acidic.
To find for the OH- concentration, we must
remember that the product of H+ and OH- is equivalent to 10^-14. Therefore,
[H+]*[OH-] = 10^-14 <span>
</span>[OH-] = 10^-14 / [H+]
[OH-] = 10^-14 / 3.25 × 10-2
[OH-] = 3.08 × 10-13 M
Answers:
Acidic
[OH-] = 3.08 <span>× 10-13 M</span>
1500 cm^3 ; 1 mL equals 1 cm^3
Answer: A. 4 unpaired electrons
B. Zero unpaired electrons
C. 1 unpaired electron
D. 5 unpaired electrons
E. Zero unpaired electrons
Explanation:
In A, Oxidation state of Co is +3 and Electronic configuration is [Ar]3d6
F is weak field ligand, causes no pairing of Electrons hence it has 4 unpaired electrons&2 are paired in t2g orbitals (dXY)
In B , Mn is in +3 with electronic configuration 3d4&CN is a strong field ligand hence causes pairing of Electrons hence it results 0 unpaired electron
In C, Mn is in +2 with electronic configuration 3d5 sinceCN is a strong field ligand hence it leaves one unpaired electron
In D, Mn is in+2 with 3d5& five unpaired electrons since cl is a weak field ligand causes no pairing.
In E, Rh is in +3, with d6 configuration and it is a low spin complex hence pairing of Electrons involved. So it leaves zero unpaired electrons.
Answer:
The percent of ethanol is 0.1093%
Explanation:
Given:
t = time = 10 s
I = current = 320 mA
F = Faraday's constant = 96485.3365 C mol⁻¹
n = number of electrons = 4
Molecular weight of ethanol = 46 g/mol
Question: What percent (by volume) of the driver's breath is ethanol, %E = ?
First, it is necessary to calculate the mass of ethanol:
The moles of ethanol:
Applying the equation of ideal gas:
Here:
T = 26°C = 299 K
P = 1 atm
Substituting values:
The percent of ethanol:
%
