How much salt (NaCl) is carried by a river flowing at 30.0 m3/s and containing 50.0 mg/L of salt? Give your answer in kg/day.
1 answer:
Answer:
129,600kg/day
Explanation:
The river is flowing at 30.0
1 = 1000L
Multiply by 1000 to convert to L/s
flowrate of river = 30*1000 =30,000L/s
Convert L/s to litre per day by multiplying by 24*60*60
flowrate of river = 30,000 * 24*60*60 L/day
= 2,592,000,000L/day
if the river contains 50mg of salt in 1L of solution
lets find how many mg of salt (X) is contained in 2,592,000,000L/day
X=
X= 129,600,000,000 mg/day
convert this value to kg/day by multiply by
X= 129,600kg/day
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Answer:
154.0831 g
Explanation:
The formula for the calculation of moles is shown below:
Given: For
Given mass = 41.0 g
Molar mass of = 24.31 g/mol
Moles of = 41.0 g / 24.31 g/mol = 1.6865 moles
Given: For
Given mass = 175 g
Molar mass of = 162.2 g/mol
Moles of = 175 g / 162.2 g/mol = 1.0789 moles
According to the given reaction:
3 moles of Mg react with 2 moles of
1 mole of Mg react with 2/3 moles of
1.6865 mole of Mg react with (2/3)*1.6865 moles of
Moles of = 1.1243 moles
Available moles of = 1.0789 moles
Limiting reagent is the one which is present in small amount. Thus, is limiting reagent. (1.0789 < 1.1243)
The formation of the product is governed by the limiting reagent. So,
2 moles of gives 3 moles of magnesium chloride
1 mole of gives 3/2 moles of magnesium chloride
1.0789 mole of gives (3/2)*1.0789 moles of magnesium chloride
Moles of magnesium chloride = 1.61835 moles
Molar mass of magnesium chloride = 95.21 g/mol
Mass of magnesium chloride = Moles × Molar mass = 1.61835 × 95.21 g = 154.0831 g