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Karolina [17]
1 year ago
10

Why is it necessary to assign organic chemistry exclusively to the study of carbon compounds?​

Chemistry
1 answer:
bonufazy [111]1 year ago
3 0

Answer:

the significant of carbon.A compound found mainly in living things is known as an organic compound make up the cells and other structures of organism and carry out life processes.Carbon is the main element in organic compound,so carbon is essential to life on earth

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After a reaction, a new compound contains 0.73 g Mg and 0.28 g N. What is the empirical formula of this compound?
FromTheMoon [43]

Answer:

Mg₃N₂

Explanation:

The empirical formula of a chemical compound is defined as the simplest positive integer ratio of atoms present in a compound. Using molecular mass of Mg (24,305g/mol) and mass of nitrogen (14,006g/mol), moles of each element are:

0,73g × (1mol / 24,305g) = 0,03 moles of Mg

0,28g × (1mol / 14,006g) = 0,02 moles of N

Dividing each value in 0,01 to obtain natural numbers:

0,03 moles of Mg / 0,01 = 3

0,02 moles of N / 0,01 = 2.

Thus, empirical formula is: <em>Mg₃N₂</em>

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I hope it helps!

5 0
1 year ago
Recall that your hypothesis is that these values are the fraction of atoms that are still radioactive after n half-life cycles.
jolli1 [7]

Answer : A= 0.5, B = 0.25 , C = 0.125, D = 0.015625 and E = 0.00390625

Explanation :

Half life of a substance is defined as the amount of time taken by the substance to reduce to half of its original amount.

Here n represents the number of half lives.

The amount of substance that remains after n half lives can be calculated using the given formula, 0.5^{n}

So when we have n =1,

Fraction of substance that remains = 0.5¹ = 0.5.

That means after first half life over, the amount of substance that remains is 0.5 times that of original.

Therefore we have A = 0.5

When n = 2, we have 0.5² = 0.25

So when 2 half lives are over, the amount of substance that remains is 0.25 times that of original

Therefore B = 0.25

When n = 3, we have 0.5³ = 0.125

So when 3 half lives are over, the amount of substance that remains is 0.125 times that of original.

Therefore we have C = 0.125

When n = 6 , we have 0.5⁶ = 0.015625

So D = 0.015625

When n = 8, we have 0.5⁸ = 0.00390625

Therefore E = 0.00390625

The values for A, B, C, D and E are 0.5, 0.25, 0.125, 0.015625 and 0.00390625 respectively.

8 0
2 years ago
Read 2 more answers
For a pure substance, the liquid and gaseous phases can only coexist for a single value of the pressure at a given temperature.
anastassius [24]

Answer:

No, it is not.

Explanation:

Most solutions do not behave ideally. Designating two volatile  substances as A and B, we can consider the following two cases:

Case 1: If the intermolecular forces between A and B molecules are weaker than  those between A molecules and between B molecules, then there is a greater tendency  for these molecules to leave the solution than in the case of an ideal solution. Consequently,  the vapor pressure of the solution is greater than the sum of the vapor  pressures as predicted by Raoult’s law for the same concentration. This behavior gives  rise to the positive deviation.

Case 2: If A molecules attract B molecules more strongly than they do their own  kind, the vapor pressure of the solution is less than the sum of the vapor pressures as  predicted by Raoult’s law. Here we have a negative deviation.

The benzene/toluene system is an exception, since that solution behaves ideally.

8 0
2 years ago
When a sample of oxygen gas in a closed container of constant volume is heated until its absolute temperature is doubled, which
saul85 [17]

Answer: b. pressure

Explanation:

Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.

P\propto T     (At constant volume and number of moles)

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1 = initial pressure of gas  = p

P_2 = final pressure of gas  = ?

T_1 = initial temperature of gas  = t

T_2 = final temperature of gas = 2t

\frac{p}{t}=\frac{P_2}{2t}

P_2=2p

Thus the pressure also doubles when absolute temperature is doubled.

7 0
2 years ago
Consider the reaction: 2clf3(g) + 2nh3(g) → n2(g) + 6hf(g) + cl2(g) when calculating the δh°rxn, why is the δhf° for n2 not impo
Leni [432]

<span>Actually, the heat of reaction hrxn s calculated by taking the sum of the heats of formation of the products minus the sum of the heats of formation of the reactants. However, at heat of formations of pure elements at atmospheric conditions is zero, therefore the hf of N2 is not important since it is zero anyway.</span>

8 0
2 years ago
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