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oee [108]
2 years ago
6

Consider the following information. The lattice energy of CsCl is Δ H lattice = − 657 kJ/mol. The enthalpy of sublimation of Cs

is Δ H sub = 76.5 kJ/mol. The first ionization energy of Cs is IE 1 = 376 kJ/mol. The electron affinity of Cl is Δ H EA = − 349 kJ/mol. The bond energy of Cl 2 is BE = 243 kJ/mol. Determine the enthalpy of formation, Δ H f , for CsCl ( s ) .
Chemistry
2 answers:
AlladinOne [14]2 years ago
8 0

Answer:

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Explanation:

andrew-mc [135]2 years ago
3 0

Answer:

-310.5 kJ/mol

Explanation:

The CsCl(s) will be formed by steps:

  • The metal (Cs) will be made gaseous by a sublimation → ΔHsub = 76.5 kJ/mol;
  • The metal gains energy to ionize → IE = 376 kJ/mol;
  • The nonmetal (Cl) loses energy to ionizes → EA = -349 kJ/mol;
  • The nonmetal is bonded → BE = 243 kJ/mol;
  • The lattice is formed → ΔHlattice = -657 kJ/mol.

The enthanlpy of formation is the sum of all the energies involved in the steps:

ΔHf = 76.5 + 376 -349 + 243 -657

ΔHf = -310.5 kJ/mol

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Answer:

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Explanation:

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vivado [14]

Answer:

Explanation:

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nadya68 [22]
The ratio of moles of reactants to moles of products can be seen from the coefficients in a balanced equation. In our case  4 moles of hydrochloric acid reacts with one mole of oxygen to produce two moles of chlorine and water.  So, <span> the ratio of moles of hydrochloric acid to moles of chlorine is 2:1. To determine the number moles, divide the mass by the mass of one mole. </span>
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<span>This is approximately 344.45 grams. 
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Usually units of this are in g per L. So, it is equivalent to 1 g / 5 L
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2 years ago
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