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sergeinik [125]
2 years ago
10

Sodium carbonate (Na2CO3) is available in very pure form and can be used to standardize acid solutions. What is the molarity of

an HCl solution if 24.3 mL of the solution is required to react with 0.246 g of Na2CO3?
Chemistry
1 answer:
NeX [460]2 years ago
7 0

Answer:

Molarity of HCl = 0.19 M

Explanation:

Moles of Na_2CO_3:-

Mass = 0.246 g

Molar mass of Na_2CO_3 = 105.988 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{0.246\ g}{105.988\ g/mol}

Moles_{Na_2CO_3}= 0.002321\ mol

According to the given reaction:-

Na_2CO_3+2HCl\rightarrow 2NaCl+H_2O+CO_2

1 mole of Na_2CO_3 react with 2 moles of HCl

0.002321 mole of Na_2CO_3 react with 2*0.002321 moles of HCl

Moles of HCl = 0.004642 moles

Given that volume = 24.3 mL

Also,  

1\ mL=10^{-3}\ L

So, Volume = 24.3 / 1000 L = 0.0243 L

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity=\frac{0.004642}{0.0243}

<u>Molarity of HCl = 0.19 M </u>

<u></u>

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Answer : Below are three ways described in brief for improving the quality of indigenous soap.

1) Add virgin coconut oil which serves as a softener and betel leaf extract. It is used to improve the quality of soap as an antimicrobial agent.

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4 0
2 years ago
Assuming ideal solution behavior, what is the freezing point of a solution of 9.04 g of I2 in 75.5 g of benzene?
cluponka [151]

Answer:

3.1°C

Explanation:

Using freezing point depression expression:

ΔT = Kf×m×i

<em>Where ΔT is change in freezing point, Kf is freezing point depression constant (5.12°c×m⁻¹), m is molality of the solution and i is Van't Hoff factor constant (1 For I₂ because doesn't dissociate in benzene).</em>

Molality of 9.04g I₂ (Molar mass: 253.8g/mol) in 75.5g of benzene (0.0755kg) is:

9.04g ₓ (1mol / 253.8g) = 0.0356mol I₂ / 0.0755kg = 0.472m

Replacing in freezing point depression formula:

ΔT = 5.12°cm⁻¹×0.472m×1

ΔT = 2.4°C

As freezing point of benzene is 5.5°C, the new freezing point of the solution is:

5.5°C - 2.4°C =

<h3>3.1°C</h3>

<em />

3 0
2 years ago
A container holds 15.0 g of phosphorous gas at a pressure of 2.0 atm and a temperature of 20.0 Celsius. What is the density of t
erik [133]
<span>Density is a value for mass, such as kg, divided by a value for volume, such as m3. Density is a physical property of a substance that represents the mass of that substance per unit volume. We calculate as follows:

PV = nRT
PV = mRT/ Molar mass
m/V = P(molar mass)/RT
Density = P(molar mass)/RT 
Density = 2.0 ( 30.97 ) / 0.08206 ( 20 + 273.15) = 2.57 g/L <----First option</span>
5 0
2 years ago
Read 2 more answers
For the reaction A+B↽−−⇀C+D, assume that the standard change in free energy has a positive value. Changing the conditions of the
77julia77 [94]

Explanation:

a. Adding a catalyst

no effect .( Catalyst can only change the activation energy but not the free energy).

b. increasing [C] and [D]

Increase the free energy .

c. Coupling with ATP hydrolysis

decrease the free energy value .

d.Increasing [A] and [B]

decrease the free energy.

7 0
2 years ago
A student titrates 10.00 milliliters of hydrochloric acid of unknown molarity with 1.000 m naoh. it takes 21.17 milliliters of b
Dima020 [189]
Mole ratio for the reaction is 1:1
no of moles in NaOH that reacted= 1*21.17/1000=0.02117mols
 molarity of HCl=0.02117*10/1000
                         =2.117M
4 0
2 years ago
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