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2 years ago

A molecule of an unsaturated hydrocarbon must have(1) at least on single carbon-carbon bond

Chemistry

2 answers:

tiny-mole [99]2 years ago

8 0

Answer:

(2) at least one multiple carbon-carbon bond

Explanation:

Hydrocarbons are organic compounds containing carbon (C) and hydrogen (H) atoms. Here, the skeletal structure is defined by the carbon-carbon bonds in which the C atoms can be linked to form linear chains or cyclic structures.

The C-C bonds in hydrocarbons are covalent in nature. The bonds can be single or multiple bonds. Structures in which the C atoms are linked by single bonds are called saturated hydrocarbons whereas multiple bonds between C atoms results in unsaturated hydrocarbons.

Therefore, a molecule of an unsaturated hydrocarbon must have at least one carbon-carbon multiple bond. The simplest example is ethene (C2H4) in which the C-C atoms are connected by a double bond.

Ethene → H2C=CH2

Romashka-Z-Leto [24]2 years ago

6 0

An unsaturated hydrocarbon has a double or triple C-C bond as unsaturated literally means it is not saturated with atoms so there are "spare bonds" left.

Therefore:

A molecule of an unsaturated hydrocarbon must have 2 - at least one multiple Carbon-Carbon bond.

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If 2.0 ml of 6.0m hcl is used to make a 500.0-ml aqueous solution, what is the molarity of the dilute solution?

svp [43]

Make sure that you understand what they are asking you from this question, as it can be confusing, but the solution is quite simple. They are stating that they want you to calculate the final concentration of 6.0M HCl once a dilution has been made from 2.0 mL to 500.0 mL. They have given us three values, the initial concentration, initial volume and the final volume. So, we are able to employ the following equation:

C1V1 = C2V2
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2 years ago

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What is the number of moles of solute in 650ml of a 0.40M solution?

Doss [256]

V=650 ml = 0.65 l

c=0.4 mol/l

n=vc

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2 years ago

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List the following compounds in decreasing electronegativity difference. cl2 hcl nacl

Mkey [24]

Based on Pauling Scale, electro negativity of Cl = 3.2, Na = 0.9 and H = 2.1

Thus, Electronegativity difference  in $Cl_{2}$ = 3.2 -3.2 = 0
Electronegativity difference  in NaCl = 3.2-0.9 = 2.3
Similarly, Electronegativity difference  in HCl = 3.2 - 2.1 = 1.1

Thus, among the listed molecules following is the decreasing order of electronegativity difference: NaCl> HCl > $Cl_{2}$

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1 year ago

The compound 1,1-difluoroethane decomposes at elevated temperatures to give fluoroethylene and hydrogen fluoride: CH3CHF2(g) → C

Maru [420]

Answer : The final temperature would be, 791.1 K

Explanation :

According to the Arrhenius equation,

$K=A\times e^{\frac{-Ea}{RT}}$

or,

$\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$K_1$ = rate constant at $460^oC$ = $5.8\times 10^{-6}s^{-1}$

$K_2$ = rate constant at $T_2$ = $4\times K_1$

$Ea$ = activation energy for the reaction = 265 kJ/mol = 265000 J/mol

R = gas constant = 8.314 J/mole.K

$T_1$ = initial temperature = $460^oC=273+460=733K$

$T_2$ = final temperature = ?

Now put all the given values in this formula, we get:

$\log (\frac{4\times K_1}{K_1})=\frac{265000J/mol}{2.303\times 8.314J/mole.K}[\frac{1}{733K}-\frac{1}{T_2}]$

$T_2=791.1K$

Therefore, the final temperature would be, 791.1 K

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2 years ago

Please help with these three questions.

scoundrel [369]

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2 years ago