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frez [133]
2 years ago
7

What is the number of moles of solute in 650ml of a 0.40M solution?

Chemistry
2 answers:
Doss [256]2 years ago
8 0
V=650 ml = 0.65 l

c=0.4 mol/l

n=vc

n=0.65 l * 0.4 mol/l = 0.26 mol
spayn [35]2 years ago
8 0
Given the concentration as molarity, we can use the following formula to solve for the moles

moles= Molarity x Liters

Molarity= 0.40 M
liters= 650 mL= 0.650 L

moles= 0.40 x 0.650 = 0.26 moles
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The highest energy occupied molecular orbital in the li−li bond of the li2 molecule is _____.
Lynna [10]
The answer is toluene I think
4 0
1 year ago
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2. Suggest four ways in which the concentration of PH3 could be increased in an equilibrium described by the following equation:
Nesterboy [21]

Answer

  • increase in temperature
  • decrease in pressure
  • continuous removal of PH3
  • adding more of P into the system

Explanation:

        In the reaction   P4(g)+6H2(g) ⇌ 4PH3(g);

  • The effect of temperature on equilibrium has to do with the heat of reaction. Recall that for an endothermic reaction, heat is absorbed in the reaction, and the value of ΔH is positive. Thus, for an endothermic reaction, we can picture heat as being a reactant:

        heat+A⇌BΔH=+

  • Since the reaction is endothermic reaction, heat is a absorbed. Decreasing the temperature will shift the equilibrium to the left, while increasing the temperature will shift the equilibrium to the right forming more of PH3.
  • According to Le Chatelier’s principle, adding additional reactant to a system will shift the equilibrium to the right, towards the side of the products. In the same Way, reducing the concentration of the product will also shift equilibrium to the right continually forming PH3 as it is removed.

4 0
1 year ago
What orbitals are used to form the 10 sigma bonds in propane (ch3ch2ch3)? Label each atom with the appropriate hybridization. Dr
SVETLANKA909090 [29]

Mixing of pure orbitals having nearly equal energy to form equal number of completely new orbitals is said to be hybridization.

For the compound, CH_3CH_2CH_3 the electronic configuration of the atoms, carbon and hydrogen are:

Carbon (atomic number=6): In ground state= 1s^{2}2s^{2}2p^{2}

In excited state: 1s^{2}2s^{1}2p^{3}

Hydrogen (atomic number=1): 1s^{1}

All the bonds in the compound is single bond(\sigma-bond) that is they are formed by head on collision of the orbitals.

The structure of the compound is shown in the image.

The Carbon-Hydrogen bond is formed by overlapping of s-orbital of hydrogen to p-orbital of carbon.

In order to complete the octet the required number of electrons for carbon is 4 and for hydrogen is 1. So, the electron in 1s^{1} of hydrogen will overlap to the 2p^{3}-orbital of carbon.

Thus, the hybridization of Hydrogen is s-hybridization and the hybridization of Carbon is sp^{3}-hybridization.

The hybridization of each atom is shown in the image.

3 0
1 year ago
All of the following reactions can be described as displacement reactions except:____________.
Lady_Fox [76]

Answer:

b

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In a displacement reaction, a part of one of the reactants is replaced by another reactant. In single displacement reactions, one of the reactants completely displaces and replaces part of another reactant. In double displacement reaction, cations and anions in the reactants switch partners to form products.

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Correct option = b.

8 0
1 year ago
The Atomic Mass of Al is 26.98154 g/mol. Is it possible to have 5.0 × 10^-25 g of Al? Explain.
Lesechka [4]
<span>If a mole of aluminum weighs 26.98 grams, that means 1 atom of aluminum weighs = (26.98 g/mole) / (6.023 x 10^23 atoms/mole) = 4.479 x 10^-23 grams,

</span>so, it is not possible because 1 atom weighs that much we calculated which is <span>almost 100 times more than the amount you mentioned</span>

8 0
1 year ago
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