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frez [133]
2 years ago
7

What is the number of moles of solute in 650ml of a 0.40M solution?

Chemistry
2 answers:
Doss [256]2 years ago
8 0
V=650 ml = 0.65 l

c=0.4 mol/l

n=vc

n=0.65 l * 0.4 mol/l = 0.26 mol
spayn [35]2 years ago
8 0
Given the concentration as molarity, we can use the following formula to solve for the moles

moles= Molarity x Liters

Molarity= 0.40 M
liters= 650 mL= 0.650 L

moles= 0.40 x 0.650 = 0.26 moles
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Acetaldehyde decomposes at 750 K: CH3CHO → CO + CH4. The reaction is first order in acetaldehyde and the half-life of the reacti
Degger [83]

Answer:

k = 1.3 x 10⁻³ s⁻¹

Explanation:

For a first order reaction the integrated rate law is

Ln [A]t/[A]₀ = - kt

where [A] are the concentrations of acetaldehyde in this case, t is the time and k is the rate constant.

We are given the half life for the concentration of acetaldehyde to fall to one half its original value, thus

Ln [A]t/[A]₀ = Ln 1/2[A]₀/[A]₀= Ln 1/2 = - kt

- 0.693 = - k(530s) ⇒ k = 1.3 x 10⁻³ s⁻¹

4 0
2 years ago
Determine the normality of the following solutions note the species of interest is H 95 g of PO4 3- in 100mL solution
Aliun [14]

Answer : The normality of the solution is, 30.006 N

Explanation :

Normality : It is defined as the number of gram equivalent of solute present in one liter of the solution.

Mathematical expression of normality is:

\text{Normality}=\frac{\text{Gram equivalent of solute}}{\text{Volume of solution in liter}}

or,

\text{Normality}=\frac{\text{Weight of solute}}{\text{Equivalent weight of solute}\times \text{Volume of solution in liter}}

First we have to calculate the equivalent weight of solute.

Molar mass of solute PO_4^{3-} = 94.97 g/mole

\text{Equivalent weight of solute}=\frac{\text{Molar mass of solute}}{\text{charge of the ion}}=\frac{94.97}{3}=31.66g.eq

Now we have to calculate the normality of solution.

\text{Normality}=\frac{95g}{31.66g.eq\times 0.1L}=30.006eq/L

Therefore, the normality of the solution is, 30.006 N

5 0
2 years ago
In this experiment, 0.170 g of caffeine is dissolved in 10.0 ml of water. the caffeine is extracted from the aqueous solution th
zmey [24]

solution:

Weight of caffeine is W = 0.170 gm.

Volume of water is V= 10 ml

Volume of methylene chloride which extracted caffeine is v= 5ml

No of portions n=3

Distribution co-efficient= 4.6

Total amount of caffeine that can be unextracted is given by

w_{n}=w\times[\frac{k_{Dx}v}{k_{Dx}v+v}]^n\\w_{3}=0.170[\frac{4.6\times10}{(4.6\times10+5)}]^3\\=0.170[\frac{46}{46+5}]^3\\=0.170[\frac{46}{51}]^3\\=0.170[\frac{97336}{132651}]\\=0.170\times0.734=0.125gms

amount of caffeine un extracted is 0.125gms

amount of caffeine extracted=0.170-0.125

                                                       =0.045 gms


6 0
2 years ago
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jok3333 [9.3K]

Explanation:

A polymer forms because the hydrocarbon joins with itself in a polymerization reaction.

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