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2 years ago

Element X reacts with element Y to give a product containing X3+ ions and Y2− ions.

Chemistry

1 answer:

Maksim231197 [3]2 years ago

5 0

Answer:

X₂Y₃

Explanation:

X⇒X³⁺ + 3e⁻ /×2

Y + 2e⁻ ⇒ Y²⁻ /×3

2X⇒2X³⁺ 6e⁻

3Y + 6e⁻⇒ 3Y²⁻

2X + 3Y ⇒2X³⁺ + 3Y²⁻ ⇒ X₂Y₃

Electron from one side and from other side can be shortened so we multiply half equations to get equivalent number of electrons on both side. Next step is summing these two half equations. Element Y takes two electrons from element X, so X become positive charged, and Y become negatively charged. It is very likely that element Y have greater electronegativity.

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Empirical Formula of P3O4H2?

puteri [66]

Answer:

H2 P4 O1. Explanation: In order to calculate the Empirical formula , we will assume that we have started with 10 g of the compound.

Explanation:

3 0

2 years ago

What mass of solid NaOH (97.0 % by mass) is required to prepare 1.00 L of a 10.0% solution of NaOH by mass? The density of the 1

Lelechka [254]

Answer: The mass of 97 % of NaOH solution required is 114.33 g

Explanation:

To calculate mass of a substance, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

We are given:

Density of 10 % solution = 1.109 g/mL

Volume of 10% solution = 1 L = 1000 mL (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

$1.109g/mL=\frac{\text{Mass of }10\%\text{ solution}}{1000mL}\\\\\text{Mass of }10\%\text{ solution}=1109g$

The mass of 10 % solution is 1109 g.

To calculate the mass of concentrated solution, we use the equation:

$c_1m_1=c_2m_2$

where,

$c_1\text{ and }m_1$ are the concentration and mass of concentrated solution.

$c_2\text{ and }m_2$ are the concentration and mass of diluted solution.

We are given:

$c_1=97\%\\m_1=?g\\c_2=10\%\\m_2=1109g$

Putting values in above equation, we get:

$97\times m_1=10\times 1109\\\\m_1=114.33g$

Hence, the mass of 97 % of NaOH solution required is 114.33 g

3 0

2 years ago

Which will not appear in the equilibrium constant expression for the reaction below?

n200080 [17]

Answer:

[C] carbon solid

Explanation:

Pure solids and liquids are never included in the equilibrium constant expression because they do not affect the reactant amount at equilibrium in the reaction, thus since your equation has [C] as solid it will not be part of the equlibrium equation.

5 0

2 years ago

Your little sister asks you a scientific question: "Does chocolate milk come from brown cows?" In order to answer the question,

aksik [14]

Answer:

Hey there,

Your answer is iii. Brown cows produce white milk. (1 point) and ii. Brown cows never produce chocolate milk. (1 point)

You already know from the basic understanding that chocolate comes from beans, not cows, and is added to milk, and thereby- brown cows do not produce chocolate milk. You also know that they produce white milk.

Wbob1314

if you have any questions I INSIST you ask them in the comments.

5 0

2 years ago

Functional group and bond hybridization of vanillin

lana66690 [7]

Vanillin is the common name for 4-hydroxy-3-methoxy-benzaldehyde.

See attached figure for the structure.

Vanillin have 3 functional groups:

1) aldehyde group: R-HC=O, in which the carbon is double bonded to oxygen

2) phenolic hydroxide group: R-OH, were the hydroxyl group is bounded to a carbon from the benzene ring

3) ether group: R-O-R, were hydrogen is bounded through sigma bonds to carbons

Now for the hybridization we have:

The carbon atoms involved in the benzene ring and the red carbon atom (from the aldehyde group) have a sp² hybridization because they are involved in double bonds.

The carbon atom from the methoxy group (R-O-CH₃) and the blue oxygen's have a sp³ hybridization because they are involved only in single bonds.

7 0

2 years ago