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1 year ago

What products are formed from monochlorination of (2r)−2−bromobutane at c1 and c4? draw the products using skeletal structures?

Chemistry

1 answer:

Kamila [148]1 year ago

4 0

From monochlorination of (2R)−2−bromobutane at C1 is formed (2S)-2-bromo-1-chlorobutane.

From monochlorination of (2R)−2−bromobutane at C4 is formed (2R)-3-bromo-1-chlorobutane.

According to Cahn-Ingold-Prelog rules, the priority of halogen substituents decreases in the following sequence:

-I > -Br > -Cl > -F

According to the rule, chlorine has priority over bromine, so the configuration changes at C1 substitution.

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At STP, fluorine is a gas and iodine is a solid. This observation can be explained by the fact that fluorine has

motikmotik

The answer is 4. The molecules of each material entice each other over dispersion (London) intermolecular forces. Whether a substance is a solid, liquid, or gas hinge on the stability between the kinetic energies of the molecules and their intermolecular magnetisms. In fluorine, the electrons are firmly apprehended to the nuclei. The electrons have slight accidental to stroll to one side of the molecule, so the London dispersion powers are comparatively weak. As we go from fluorine to iodine, the electrons are far from the nuclei so the electron exhausts can more effortlessly misrepresent. The London dispersion forces developed to be increasingly stronger.

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1 year ago

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29 Which term identifies a type of nuclear reaction?

AURORKA [14]

4) fission is a nuclear reaction where the nucleus of a reactant breaks apart

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1 year ago

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Freon-12, CF2Cl2, which has been widely used in air conditioning systems, is considered a threat to the ozone layer in the strat

Vilka [71]

Answer:

The root mean squared velocity for CF2Cl2 is $v_{rms}= 207.06 m/s$

Explanation:

From the question we are told that

The temperature is $T = -65 ^oC = -65+273 = 208K$

Root Mean Square velocity is mathematically represented as

$v _{rms} = \sqrt{\frac{3RT}{MW} }$

Where T is the temperature

MW is the molecular weight of gas

R is the gas constant with a value of $R = 8.314 JK^{-1} mol^{-1}$

For CF2Cl2 its molecular weight is 0.121 kg/mol

Substituting values

$v_{rms} = \sqrt{\frac{3 * 8.314 *208}{0.121} }$

$v_{rms}= 207.06 m/s$

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1 year ago

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Caffeine, a molecule found in coffee, tea, and certain soft drinks, contains C, H, O, and N. Combustion of 10.0 g of caffeine pr

denis-greek [22]

Answer:

194 g/mol.

Explanation:

Hello,

In this case, one first must compute the mass of each element as shown below:

$C=18.13gCO_2*\frac{12gC}{44gCO_2} =4.945gC\\H=4.639gH_2O*\frac{2.016gH}{18.0152gH_2O}=0.519gH\\N=2.885gN_2\\O=10.0g-4.945g-0.519g-2.885g=1.651gO$

Next, the corresponding moles:

$C=4.945gC*\frac{1molC}{12gC}=0.412mol\\H=0.519gH*\frac{1molH}{1gH}=0.519mol\\N=2.885gN*\frac{1molN}{14gN}=0.206molN\\O=1.648gO*\frac{1molO}{16gO} =0.103molO$

Then, each element's subscripts is found to be:

$C=\frac{0.412}{0.103}=4\\H=\frac{0.519}{0.103}=5\\N=\frac{0.206}{0.103} =2\\O=\frac{0.103}{0.103}=1$

Therefore, the empirical formula is:

$C_4H_5N_2O$

Nonetheless, it has a molar mass of 97bg/mol, thereby, by multiplying such formula by 2 one gets:

$C_8H_10N_4O_2$

Which has a molar mass of 194 g/mol being correctly contained in the given interval.

Best regards.

8 0

2 years ago

The mass unit associated with density is usually grams. if the volume (in ml or cm3) is multiplied by the density (g/ml or g/cm3

jok3333 [9.3K]

The weight in grams = 7.93 g

Given volume = 2.00 $in^{3}$

Given density = 0.242 g/ $cm^{3}$

We need to find the Mass(weight) in grams.

To find the weight in grams we need to keep in mind that the volume and density must use the same volume unit for cancellation. So that the volume units will cancel out, leaving only the mass units.

The unit of given volume is $in^{3}$ and unit of volume in density is $cm^{3}$ , so first we need to change the unit of volume from $in^{3}$ to $cm^{3}$ so that the volume units will cancel out, leaving only the mass units.