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Helga [31]
1 year ago
13

When 0.40 mol Al is mixed with 0.40 mol Br2, the following reaction occurs: 2Al(s) + 3Br2(l) → 2AlBr3(s) Identify the limiting r

eactant and the moles of leftover reactant, assuming the reaction goes to completion.
a. The limiting reactant is Br2, and 0.20 mol Al should remain unreacted.
b. The limiting reactant is Al, and 0.13 mol Br2 should remain unreacted.
c. The limiting reactant is Al, and 0.20 mol Br2 should remain unreacted.
d. The limiting reactant is Br2, and 0.13 mol Al should remain unreacted.
Chemistry
1 answer:
Lera25 [3.4K]1 year ago
7 0

Answer:

d. The limiting reactant is Br2, and 0.13 mol Al should remain unreacted.

Explanation:

From the reaction, 2Al(s) + 3Br2(l) → 2AlBr3(s)

2 moles of Al combines with 3 moles of Br to form 2 moles of AlBr3

Hence 1 mole of Br combines with 2/3 moles of Al

or 0.4 moles of Br combines with 2/3×0.4 moles of Al or 0.267 Moles of Al leaving

0.4 - 0.267 = 0.133 moles of Al remaining unreacted

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How many grams of NO are required to produce 145 g of N2 in the following reaction?
V125BC [204]

Answer:

b. 186 g

Explanation:

Step 1: Write the balanced equation.

4 NH₃(g) + 6 NO(g) → 5 N₂(g) + 6 H₂O(l)

Step 2: Calculate the moles corresponding to 145 g of N₂

The molar mass of nitrogen is 28.01 g/mol.

145g \times \frac{1mol}{28.01 g} =5.18 mol

Step 3: Calculate the moles of NO required to produce 5.18 moles of N₂

The molar ratio of NO to N₂ is 6:5.

5.18molN_2 \times \frac{6molNO}{5molN_2} = 6.22molNO

Step 4: Calculate the mass corresponding to 6.22 moles of NO

The molar mass of NO is 30.01 g/mol.

6.22mol \times \frac{30.01g}{mol} =186 g

4 0
1 year ago
Given equilibrium partial pressures of PNO2= 0.247 atm, PNO = 0.0022atm, and PO2 = 0.0011 atm calculate the equilibrium constant
maxonik [38]
Answer 1:
Equilibrium constant (K) mathematically expressed as the ratio of the concentration of products to concentration of reactant. In case of gaseous system, partial pressure is used, instead to concentration.

In present case, following reaction is involved:

                        2NO2    ↔      2NO + O2

Here, K = \frac{[PNO]^2[O2]}{[PNO2]^2}

Given: At equilibrium, <span>PNO2= 0.247 atm, PNO = 0.0022atm, and PO2 = 0.0011 atm
</span>
Hence,  K = \frac{[0.0022]^2[0.0011]}{[0.247]^2}
                 = 8.727 X 10^-8

Thus, equilibrium constant of reaction = 8.727 X 10^-8
.......................................................................................................................

Answer 2:
Given: <span>PNO2= 0.192 atm, PNO = 0.021 atm, and PO2 = 0.037 atm.

Therefore, Reaction quotient = </span>\frac{[PNO]^2[O2]}{[PNO2]^2}
                                              = \frac{[0.021]^2[0.037]}{[0.192]^2}
                                              = 4.426 X 10^-4.

Here, Reaction quotient > Equilibrium constant.

Hence, <span>the reaction need to go to reverse direction to reattain equilibrium </span>
5 0
2 years ago
Read 2 more answers
Micky Mo is a 64-year-old male admitted to the emergency room for asthma. His laboratory results are as follows: pH 7.31, pCO2 h
Salsk061 [2.6K]

Answer:

Micky Mo is suffering from respiratory acidosis.

Explanation:

The pCO2 level in micky"s body is higher than normal it means the excess amount of  CO2 will reacts with water to generate carbonic acid(H2CO3).

  On the other hand according to the question total HCO3- also higher than normal.As a result the excess HCO3- will react with proton to form carbonic acid which is in turn dissociate to generate CO2 and H2O to maintain normal acid base homeostasis.

 From that point of view it can be said Micky Mo is suffering from respiratory acidosis.

5 0
1 year ago
identify the element in period 3 that requires the least amount of energy to remove the most loosely held electrons from a mole
OLga [1]

Answer:

The element is Na

Explanation:

Ionization energy is the energy needed to release the last electron from an atom in its ground state to the gaseous state.  It is a periodic property that increases as we go through the periods of the periodic table, but decreases if we move in groups.  Sodium has thr ionic radius (another periodic property) that is too large, making it easier to release the electron away, since it is too far from the nucleus.

3 0
1 year ago
Na (atomic no. 11) reacts with Cl (atomic no. 17) to become stable. In the reaction, Na will ____________, while Cl will _______
nignag [31]

Answer:

Sodium will an electron and chlorine will gain an electron

Explanation:

The electronic configurations of sodium and chlorine are;

Sodium- 1s2 2s2 2p6 3s1

Chlorine- 1s2 2s2 2p6 3s2 3p5

Hence, sodium can easily loose one electron to chlorine to attain a noble gas configuration while chlorine accepts one electron to attain the noble gas configuration.

8 0
1 year ago
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