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Vera_Pavlovna [14]
1 year ago
12

After a reaction, a new compound contains 0.73 g Mg and 0.28 g N. What is the empirical formula of this compound?

Chemistry
1 answer:
FromTheMoon [43]1 year ago
5 0

Answer:

Mg₃N₂

Explanation:

The empirical formula of a chemical compound is defined as the simplest positive integer ratio of atoms present in a compound. Using molecular mass of Mg (24,305g/mol) and mass of nitrogen (14,006g/mol), moles of each element are:

0,73g × (1mol / 24,305g) = 0,03 moles of Mg

0,28g × (1mol / 14,006g) = 0,02 moles of N

Dividing each value in 0,01 to obtain natural numbers:

0,03 moles of Mg / 0,01 = 3

0,02 moles of N / 0,01 = 2.

Thus, empirical formula is: <em>Mg₃N₂</em>

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I hope it helps!

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Design a synthesis of 2-ethyl-2-hexenoic acid from alcohols of four carbons or fewer.
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Answer:

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Explanation:

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4 0
2 years ago
The polymer formed from the monomer ch2=ch–cn is select one:
podryga [215]
Answer:
             None of the given options show polymer made up of H₂C=CH-CN (Acrylonitrile).

Explanation:
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                                             --(H₂C-CHCN-)n--

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The polymerization is shown below,

5 0
2 years ago
If a pharmacist added 12 g of azelaic acid diluent should be used to prepare 8 fluidto 50 g of an ointment containing 15% ounces
natta225 [31]
Answer is: 31,45%.
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mr</span>₂(C₉H₁₆O₄) = 50g.
ω₂(C₉H₁₆O₄) = 15% = 0,15.
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7 0
2 years ago
How many chloride ions are in a 220 grams of calcium chloride?
fomenos
The Ions present in CaCl₂ are,

                                                 Ca²⁺    Cl⁻     Cl⁻

Means 1 formula unit contains 1 Ca²⁺ ion and 2 Cl⁻ ions.

Also, 1 mole of CaCl₂ contains 6.022 × 10²³ formula units.

So, 1 mole formula units of CaCl₂ contain,

                                            2 × 6.022 × 10²³  =  1.20 × 10²⁴ Cl⁻ Ions

Now, Calculating number of moles contained by 220 g of CaCl₂,
As,
                               110.98 g of CaCl₂  =  1 mole
Then, 
                                    220 g of CaCl₂  =  X moles
Solving for X,
                                                 X  =  (220 g × 1 mol) ÷ 110.98 g

                                                 X  =  1.98 moles
As,
                           1 mole contained  =  1.20 × 10²⁴ Cl⁻ Ions
Then,
                    1.98 mole will contain  =  X Cl⁻ Ions
Solving for X,
                                                  X  =  (1.98 mol × 1.20 × 10²⁴ Ions) ÷ 1mol

                                                  X  =  2.38 × 10²⁴ Cl⁻ Ions
6 0
1 year ago
Read 2 more answers
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