Answer:- 0.138 M
Solution:- The buffer pH is calculated using Handerson equation:

acts as a weak acid and
as a base which is pretty conjugate base of the weak acid we have.
The acid hase two protons(hydrogen) where as the base has only one proton. So, we could write the equation as:

Phosphoric acid gives protons in three steps. So, the above equation is the second step as the acid has only two protons and the base has one proton.
So, we will use the second pKa value. The acid concentration is given as 0.10 M and we are asked to calculate the concentration of the base to make a buffer of exactly pH 7.00.
Let's plug in the values in the equation:



Taking antilog:


On cross multiply:
[base] = 1.38(0.10)
[base] = 0.138
So, the concentration of the base that is
required to make the buffer is 0.138M.
The answer to this question is "carrying capacity." The term "growth
rate," refers to how fast a population grows, and the term "population
density," refers to the number of organisms located within a specific
area. Carrying capacity is correct because is directly addresses the
maximum number of organisms that an ecosystem can handle, as opposed to
how fast they are growing or how many there currently are.
Answer:
Helium.
Explanation:
Hydrogen in the bomb is used in the process of detonation. A stream of tritium, an isotope of hydrogen is released and this fissionable material is very unstable thus it turns during the detonation to helium 3. This triggers a series of reactions that produce large amounts of heat to the surrounding environment causing destruction.
C. Visible light does not produce transitions between electronic energy levels in the N₂ molecule but does produce transitions in the I₂ molecule.
Explanation:
Abortion of light by molecules will produce electronic transitions from a ground level to a higher level equal to the energy of absorbed light.
In the case of nitrogen (N₂) the allowed electronic transitions are between electronic energy levels with a energy difference equal to the energy of photons of the ultraviolet light. Nitrogen will not absorb from the visible range so it is colorless.
Now iodine (I₂) have the allowed electronic transitions between electronic energy levels with a energy difference equal to the energy of photons of the visible light. As a consequence Iodine vapors have a violet color.
Learn more about:
electronic transitions
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